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七年级下册英语完型填空

一、选一选（每小题有4个选项，其中有且只有一个正确，请把正确选项的编码填入答题卷的相应空格内，每小题3分，共30分）

1．下列各组数不可能组成一个三角形的是………………………………………（）（A）3，4，5 （B）7，6，6 （C）7，6，13 （D）175，176，177

2．已知某种植物花粉的直径为0.00035米，用科学记数法表示该种花粉的直径是（）（A）3.5×10 米（B）3.5×10 米（C）3.5×10 米（D）3.5×10 米

3．如图，由平移得到的三角形有几个……（）

（A）3 （B）5

（C）7 （D）15

4．小马虎在下面的计算中只做对了一道题，他做对的题目是…………………………………………………（）

（A）（B）（C）（D）

5．4张扑克牌如图（1）所示放在桌子上，小敏把其中一张旋转180o后得到如图（2）

所示，那么她所旋转的牌从左数起是………………………………………（）（A）第一张（B）第二张（C）第三张（D）第四张

6．从1、2、3、4四个数中任意取两个求和，其结果最有可能是…………………（）（A）3 （B）4 （C）5 （D）6

7．王老师的一块三角形教学用玻璃不小心打破了（如图），

他想再到玻璃店划一块，为了方便他只要带哪一块就可以了……………………………………………………（）

（A）①（B）②

（C）③（D）④

8．方程组的解是………………………………………………………（）（A）（B）（C）（D）

9．古代有这样一个寓言故事：驴子和骡子一同走，它们驮着不同袋数的货物，每袋货物都是一样重的。驴子抱怨负担太重，骡子说：“你抱怨干嘛,如果你给我一袋，那我所负担的就是你的两倍；如果我给你一袋，我们才恰好驮的一样多！”那么驴子原来所驮货物的袋数是……………………………………………………（）

（A）5 （B）6 （C）7 （D）8

10．义乌国际小商品博览会某志愿小组有五名翻译，其中一名只会翻译阿拉伯语，三名只会翻译英语，还有一名两种语言都会翻译．若从中随机挑选两名组成一组，则该组能够翻译上述两种语言的概率是（）

A．B．C．D．

二、填一填（请把正确答案填入相应横线上，每小题3分，共30分）

11．当 = 时，分式的值为零。

12．分解因式：

13．计算：

14．全等三角形的对应边，对应角。

15．暗箱里放入除颜色外其他都相同的10个球，其中4个黑球，6个白球，搅拌均匀后任取一个球，取到是黑球的概率是 .

16．如图，平面镜A与B之间夹角为，光线经

平面镜A反射到平面镜B上，再反射出去，若

，则的度数为

17．若非零实数满足，则

18．五根木棒长分别为1、2、3、4、5分米，用其中

三根围成三角形，可以围成个不同三角形。

19．如图，≌，点和点是对应顶点，

，，，则

㎝.

20. 观察下列各式，你发现什么规律：

请你将猜想到的规律用只含有一个字母的等式表示出来 .

三、解一解（共40分）

21．（本题6分）如下图，由小正方形组成的L形图中，请你用三种方法分别在图中添画一个小正方形，使它成为轴对称图形：

22．（本题12分）计算下列各式

（1）（2）

（3）分解因式 (4) 先化简：，并找一个你喜欢的

数代入求值。

23．(本题6分) 解方程：

24．甲、乙两同学玩“托球赛跑”游戏，商定：用球拍托着乒乓球从起跑线l起跑，绕过P点跑回到起跑线（如图所示）；途中乒乓球掉下时须捡起并回到掉球处继续赛跑，用时少者胜．结果：甲同学由于心急，掉了球，浪费了6秒钟，乙同学则顺利跑完．事后，甲同学说：“我俩所用的全部时间的和为50秒”，乙同学说：“捡球过程不算在内时，甲的

速度是我的1.2倍”．根据图文信息，请问哪位同学获胜？

25．(本题9分) 如图是由转盘和箭头组成的两个装置，装置A、B的转盘分别被分成三个面积相等的扇形，装置A上的数字分别是2，6，8，装置B上的数字分别是4，5，7，这两个装置除了表面数字不同外，其他构造完全相同。现在你和另外一个人分别同时用力转动A、B两个转盘中的箭头，如果我们规定箭头停留在较大数字的一方获胜（若箭头恰好停留在分界线上，则重新转动一次，直到箭头停在某一个数字为止），那么你会选择哪个装置呢？请借助列表法或树状图说明理由。

26、如图，已知正方形ABCD中，边长为10cm,点E在AB边上，BE=6cm.

(1)如果点P在线段上以4cm/s的运动速度由点B向点C运动，同时，点Q在线段CD上由点C向点D运动。

①若点Q的运动速度与点P的运动速度相等，经过一秒后，三角形BPE与三角形CQP是否全等，请说明理由；

②若点Q的运动速度与点P的运动速度不相等，当点Q的运动速度为多少时，能够使△BPE 与△CQP全等？

（2）若点Q以②中的运动速度从点C出发，点P以原来的运动速度从点B同时出发，都逆时针沿正方形ABCD四边运动，求经过多长时间点P与点Q第一次在正方形ABCD的何处相遇？

参考答案

一、选一选

1. C

2. B

3.B

4. C

5. A

6. C

7.A

8. A

9. A 10. C

提示: 5. 根据扑克牌上的图案; 6. 1+4=5, 2+3=5; 7. 选A,根据ASA;

9.设驴子原来所驮的货物是袋, 骡子所驮的货物是袋,则列出方程组为

10.

二、填一填

11. 3 12. 13. 14. 相等;相等 15.

16. 17. 2 18. 3 19. 5 20.

提示: 15. P(黑)= ; 16. ; 17. ;

18. 2、3、4; 3、4、5; 2、4、5

三、解一解

21. 每画出一种得2分

22. (1) 解:原式= …………………………1分

= ………………………………………1分

(2) 解:原式= …………………………2分

= ………………………………………1分

(3) 解:原式= ………………………………1分

= ……………………………………2分

(4) 解:原式= ……………………………1分

求值答案不唯一,可以取除了1以外的任何数…………… 2分23. 解:去分母,得………… 1分

去括号,得………… 1分

移项,合并同类项,得………… 1分

把左边分解因式,得………… 1分

∴ , ………… 1分

经检验是增根舍去,所以原方程的根是 . … 1分

24. BM ( 线段中点的意义) ;

(已知) ; (已知) ; BM

(AAS)

AC=BD (全等三角形的对应边相等) (每空0.5分)

25. 选择A装置

4 （2，4）

2 5 （2，5）

7 （2，7）

4 （6，4）

开始 6 5 （6，5）

7 （6，7）

4 （8，4）

8 5 （8，5）

7 （8，7）………… 4分或

A 4 5 7

2 （2，4）（2，5）（2，7）

6 （6，4）（6，5）（6，7）

8 （8，4）（8，5）（8，7）

P（A）= ，P（B）= ………………………………… 4分∵P（A）＞P（B），∴选择A装置…………………………1分

1、BP=CQ=4，∴PC=BE=6，∵∠B=∠C=90°，∴△BPE≌△CQP。

2、设出发t秒时，两个三角形全等，BP=4t，CP=10-4t，

①△BPE≌△CQP，PC=BE=6，∴PB=4，∴CQ=4，就是⑴中的情况，不合题意，舍去。

②△BPE≌△CPQ，这时BP=CP=5，t=5/4，CQ=BE=6，6÷5/4=24/5，即Q的速度为24/5cm/s ⑵属于追及问题，P、Q相距10cm，Q的速度为2cm/s，P的速度为4cm/s，设t秒追上。

2t+10=4t，t=5，Q点5秒走到点D，即第一次P追上Q在点D处。

(完整版)初一上册英语完形填空试题

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