解:(1)由方程可得,乙醇平均摩尔汽化热/R=5306.8J,∴△vHm=44.12KJ/mol (2)当P*=101.43Kpa时,y=ln101.43=4.62,
代入方程得, x=(4.62-19.799)/(-5306.8)=0.00286,
∴T=1/0.00286=349.6K,
∴乙醇沸点=349.6K-273K=76.70℃。
(3)相对测量误差=(78.37-76.70)/78.37*100%=2.13%