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大学《数据库原理》期末考试试题及答案(一)

大学《数据库原理》期末考试试题及答案(一)
大学《数据库原理》期末考试试题及答案(一)

一、填空题

1.标准的数据库三级模式是概念模式、(内)模式和(外)模式。

2.数据完整性约束分为(静态)约束和(动态)约束。

3.分布式数据库系统的特点是数据的(分布)性和整体的(逻辑)性。

4.在数据库系统中,所有应用程序都通过(DBMS)访问数据库。

5.在数据库的三级模式结构中,数据是按(内)模式的描述存储在磁盘中,按(外)模式提供给用户的。

6.在关系中,能唯一标识元组的属性称为(超键)。

7.在对象关系模型中,属性的符合类型包括:多集类型、数组类型、(结构)类型和(集合)类型。

8.对于函数依赖x→Y,如果Y是X的子集,此函数称为(平凡)函数依赖。

方法的三要素是:实体、属性和(联系)。

10.假设两个事务同时存取同一个数据集,当第一个事务结束之前,第二个事务更新数据库,这就违反了事务的(隔离)性,破坏了DB

的一致性。

11.假设一个学生只属于一个班级,则班级和学生之间是(一对多,1:N)联系;学生可以同时修多门课程,学生和课程之间是(多对多,M:N)联系。

12.结构数据模型的组成包括:数据结构,(数据操作)和(数据完整性约束)。

13.在函数依赖中,平凡的函数依赖根据Armstrong推理规则中的(自反)律就可推出。

14.用有向图结构表示实体类型及实体间联系的数据模型称为(网状)模型。

15.若用户编写程序时,只需指出做什么,不需指出怎么做,这类DML 是(非过程性)DML;关系的DML属于这一类。

16.在SQL中,用(update)命令可以修改表中的数据,用(ALTER)命令可以修改表的结构。

17.在ER图中,菱形框表示(联系)。

18.物理结构设计是设计DB的物理结构,主要包括DB的(存储结构)和存取方法。

19.并发控制的主要方法是采用(封锁机制)。

20.在并行处理中,若干事物相互等待对方释放封锁,称为系统进入(死锁)状态。

的“地址透明性”位于(分片)模式和(分配)模式之间。

二、单选题

1. 位于用户和数据库之间的一层数据管理软件是( C)

2. 一个事务中所有对数据库操作是一个不可分割的操作序列,这称为事务的( A )

A.原子性

B.一致性

C.隔离性

D.持久性

3. 关系代数的五个基本操作是:并、差、选择、投影和( D )

A.等值连接连接

C.自然连接

D.笛卡儿积

4. 在关系数据库中,表与表之间的联系是通过( B )实现的。

A.实体完整性规则

B.参照完整性规则

C.用户自定义的完整性规则

D.主键

5. 数据字典产生于数据库设计步骤的( A )

A.需求分析阶段

B.概念设计阶段

C.逻辑设计阶段

D.物理设计阶段

6. 在数据库技术中,未提交的随后又被撤消的数据称为( D )

A.错误数据

B.冗余数据

C.过期数据

D.脏数据

7. 在SQL中,建立视图用的命令是( C )

SCHEMA TABLE

VIEW INDEX

8. 分布式数据库系统的透明性主要表现在位置透明性和( C )

A.数据透明性

B.处理透明性

C.复制透明性

D.映射透明性

9. 在数据库的E-R图中,菱形框表达的是( C )

A. 属性

B.实体

C.实体之间的联系

D.实体与属性之间的联系

10. 设关系R和S的结构相同,并且各有80个元组,假如这两个关系作并运算,其运算结果的元组个数为( D )

A .80 B.小于等于80 C.大于等于160 D. 大于等于80,小于等于160

11. 以下操作中,不能用DML实现的是( B )

A.数据查询

B.定义数据库的三级结构

C.数据插入

D.数据删除

12. 如果关系R和S进行自然连接时,只把S中原该舍弃的元组保存到新关系中,这种操作称为( D )

A.外连接

B.内联接

C.左连接

D.右外连接

13. 把E-R图转换成关系模型的过程,属于数据库设计的( C )

A.总体结构设计

B.概念结构设计

C.物理结构设计

D.逻辑结构设计

14. ORDBS的中文意思是( C )

A.面向对象的数据库系统

B.数据库管理系统

C.对象关系数据库系统

D.关系数据库系统

15. 在较低层上的抽象表达了与之联系的较高层上抽象的特殊情况时,称为较高层上抽象是较低层抽象的( D )

A.概括

B. 聚集

C.细化

D. 泛化

16. 在SQL中,SELECT语句的"SELECT DISTINCT"表示查询结果中( C )

A.属性名都不相同

B.去掉了重复的列

C.行都不相同

D.属性值都不相同

17. 在采用客户机/服务器体系结构的数据库应用系统中,应该将用户应用程序安装在( A )

A.客户机端

B.服务器端

C.终端

D.系统端

18. 事务日志用于保存( D )

A.程序运行过程

B.数据操作

C.程序的执行结果

D.对数据的更新操作

19. 在第一个事务以S锁方式读数据A时,第二个事务可以进行的操作是( D )

A.对数据实行X锁并读数据

B.对数据实行S锁并写数据

C.对数据实行X锁并写数据

D.不加封锁的读数据

20. 概念结构设计的目标是产生DB的概念模型,该模型主要反映( B )

的管理信息需求 B.企业组织的信息需求

C.应用程序员的编程需求的维护需求

三、名词解释

1. 部分函数依赖

关系模式中,如果X→Y, 且X存在真子集X',使X'→Y也成立, 这时称X→Y为部分函数依赖。

2.外模式

3.用户与数据库系统的接口,是面向每个用户使用的数据视图的描述。

4.

5.嵌入式SQL

6.将SQL语句嵌入高级程序设计语言中使用,发挥高级语言过程化处理能力强的特点。

4. 数据定义语言

由DBMS提供的,用于描述数据库各级模式的结构,相互之间的映像,以及安全性规则,完整性约束等内容的语言。

5. 授权

将对数据库中的某些表、某些字段的操作权限授予指定的用户,这种操作称为"授权"。

四、简答题

1. 在关系模式R(U,F)中,U=ABCDE,F={A→C,AC→B,B→D,C→E,EC→B} 计算(AB)+。

(AB)+ =ABCDE

2.简述数据库概念模型的主要特点。

(1)对现实世界的抽象和概括,能真实,充分的反映现实世界的事物和事物之间的联系

(2)简洁、明晰、独立于计算机系统、便于理解

(3)易于变动和修改

(4)易于向给定的数据库逻辑模式转换。

3.简述在SQL中,DELETE语句与DROP TABLE的区别。

DELETE的作用是删除表中的元组,表的模式依然存在,而DROP TABLE 是将表的结构和元组全部删除,表被删除(DROP)后就不再存在了。

五、程序设计题

六、以下各小题题基于教学数据库的三个基本表

七、学生S(S#,SNAME,AGE,SEX)

八、学习SC(S#,C#,GRADE)

九、课程C(C#,CNAME,TEACHER)

十、

1. 试用元组表达式和关系代数表达式表示下列查询语句:检索年龄小于23岁的男学生的学号和姓名。

关系代数表达式:πS#,SNAME(σAGE>'23'∧SEX='男'(S))

元组表达式:{t|(u)(S(u)∧u[3]>'23'∧u[4]='男'∧t[1]=u[1]∧t[2]=u[2])}

2. 试用SQL的查询语句表达下列查询: 检索"王兰"同学不学的课程的课程号。

SELECT C#

FROM C

WHERE C# NOT IN

(SELECT C#

FROM SC

WHERE S# IN

(SELECT S#

FROM S

WHERE SNAME='王兰'))

3. 试用SQL的查询语句表达下列查询: 检索全部学生都选修的课程的课程号与课程名。

SELECT C#,CNAME

FROM C

WHERE NOT EXISTS

(SELECT *

FROM S

WHERE NOT EXISTS

(SELECT *

FROM SC

WHERE #=# AND #=#))

4. 试用SQL更新语句表达以下更新操作:把低于总平均成绩的女同学成绩提高5%。

UPDATE SC

SET GRADE=GRADE*

WHERE GRADE<(SELECT AVG(GRADE) FROM SC) AND S# IN (SELECT S# FROM S WHERE SEX='F')

六、应用题

1.有一个应用,包括三个实体集。实体类型“商店”的属性有:商店编号,店名,店址,店经理。实体类型“会员”的属性有:会员编号,会员名,地址。实体类型“职工”的属性有:职工编号,职工名,性别,工资。每家商店有若干职工,但每个职工只能服务于一家商店。每家商店有若干会员,每个会员可以属于多家商店。在联系中应反映出职工参加某商店工作的开始时间,会员的加入时间。

(1)试画出反映商店、职工、会员实体类型及联系类型的ER图;

(2)将ER图转换成关系模式,并指出每个表的主键和外键;

(3)指出以上关系模式所达到的范式。

(1)

(2)

商店模式(商店编号,店名,店址,店经理)

主键:商店编号

职工模式(职工编号,职工名,性别,工资,商店编号,开始时间)

主键:职工编号外键:商店编号

会员模式(会员编号,会员名,地址)

主键:会员编号

SM模式(会员编号,商店编号,会员加入时间)

主键:会员编号,商店编号

外键:会员编号;商店编号

(3)以上关系模式中,所有属性对侯选键都不存在传递依赖,因此都是BCNF。$

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▆■■■■■■■■■■■■

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