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Unit 7 face to face with guns对照

Unit 7 face to face with guns对照
Unit 7 face to face with guns对照

Unit 7 Face to face with guns

Like most city folks, I am cautious. I scan the street and pathways for anything-or anyone-unusual before pulling into the garage. That night was no exception. But, as I walked out the garage, KFC Chicken in hand, a portly, unshaven young man in a stocking cap and dark nylon jacket emerged from the shrub by the parking pad and put his pistol between my eyes.

在手枪胁迫之下

和大多数城里人一样,我非常小心谨慎。在把车开进车库前,我会扫视街道和周围的小路,看看有没有异常的人或东西。那天晚上也不例外。可是当我手里拿着肯德基炸鸡走出车库时,一个肥壮、留着短髭、头戴绒线帽、身穿深色尼龙夹克的年轻人从停车处旁边的灌木丛中钻出来,把手枪顶在我的双眼之间。

“Give it up, mother,” he threatened. “Give it up.”

Hey, I said, just take it. As I spoke, I set the KFC chicken on the planter beside the pathway, contriving as I did so to toss my house keys into a bush.

"交出来,他妈的--,"他威胁道,"出来。"

"嗨,"我说,"去吧。"我一边说,一边把肯德基快餐盒放在小路旁边的播种机上,同时设法把我房子的钥匙扔进灌木丛中。

Where is your money? Where is your money? He barked. Everything he said during our encounter was repeated, instinctively, I did the same. It

is in my wallet, it is in my wallet, I said.

"你的钱呢?你的钱呢?"他吼道。在我们遭遇的过程中,他会重复自己说的每一句话;出于本能,我也同样重复着自己的话。"在我钱包里,在我钱包里,"我说。

He moved behind me, put his gun on my neck and begun to search my trouser pockets.

Where is your wallet? He asked.

他走到我的背后,把枪顶在我的脖子上,开始搜我的裤子口袋。

"你的钱包呢?"他问。

It is in my back pocket. Where is your rest of money? I don't have any more money. Where is your watch? Here, I replied, extending my left arm sideways. Just then, his partner appeared. Slight and shorter, he held an enlarged blue steel pistol. His dark eyes shone like polished glass; his arms and legs moved unexpectedly, as if attached to unseen wires.

"在后面的口袋里。"

"还有呢?"

"我就这么多钱了。"

"你的手表呢?"

"在这儿,"我边回答边把左臂伸向路旁。

就在这时,他的同伙出现了。他很瘦小,手持一支加大的蓝色钢制左轮手枪。他深色的眼睛里闪着光,好似擦亮了的玻璃;他手臂和双腿冷不防地移动着,就好像是连着看不见的电线似的。

His voice snapped, stop looking at me. 他厉声说道,"不许朝我们看,不许朝我们看。"He was not stupid. I’ve seen eno ugh criminal trials to know victims of armed attacks are seldom able to identify their offenders because their attentions focus on the guns, rather on their users. I consciously noticed details of their faces. I’m not looking at her, I lied as the big one ripped the watch from my wrist.

他并不蠢。我看过许多刑事审判,因而知道在那些武装袭击的受害者中,很少有人能够辨认出袭击他们的人,因为他们的注意力全集中在枪上,而没有放在持枪人上。我有意识地留意了一下他们面部的细节。

"我没有看你们。"当那个大个子劫匪把手表从我的手腕上扯下来时,我撒了个谎。

Get down, the thin ordered, he grabbed my glasses and tossed them onto the lawn. "趴下,趴下,"那小个子命令我,并一把摘下了我的眼镜,把它扔到草坪上。By then, I was flat on my face on the pathway, its dirt against my forehead. The big one’s gun dug into my back of my head, the thin one’s pistol into my left temple. I thought, I’m going to die. This

is going to kill me. Lord, have mercy on me, a sinner.

这时,我已面朝下趴在了地上,地上的尘土紧贴着我的前额。那个大个子劫匪用枪顶着我的后脑勺,小个子用左轮手枪顶着我左边的太阳穴。

我当时想,"这下完了。他们就要杀死莱斯利了。主啊,可怜可怜

我这个有罪的人吧。"

What’s this? The big one asked. I rolled my head to the right. It’s KFC chicken, I said. We will take it, the big one snapped.

"这是什么?"大个子问道。

我把头转向右边。

"是肯德基炸鸡,"我说。

"我们把它带走,"大个子厉声说道。

And suddenly-wallet, watch and chicken in hand-their footsteps faded down the darkened street. I turned to see that their shadows get into a car and speed away. I had been spared, but by what? How peculiar, I thought, to have my life saved by fried chicken. I saw eternity; they saw food.

接着,突然间---劫匪们手里拿着钱包、手表和炸鸡---他们的脚步声消失在了黑暗的街道上。

我转过身,看见他们的影子钻进了一辆汽车,急速地开走了。

他们没有杀我,但他们为什么这么做呢?是仁慈?是因为时间太紧而顾不上来?还是因为饥饿?

"多奇怪啊,"我心中暗道,"竟然是炸鸡救了我的命。当时我看见了死亡,而他们看见了食物。"

I got to my feet, found my keys, entered and called 911. The operator took a description of the robbers and sent a police car. I poured a stiff drink and, soon, two uniformed officers of the LAPD arrived. They took a report and admitted the important thing was nobody was hurt. But, one

officer said on leaving, taking your chicken, that’s rough.

LAPD:洛杉矶警察局(Los Angeles Police Department)

我站起身来,找到了钥匙,进了屋,然后拨通了911。接线员记下了我对劫匪的描述,然后派了辆警车来。我刚为自己倒了一杯烈性酒,两个穿制服的洛杉矶警察局的警察就到了。他们对此事作了笔录,说"幸好"没有伤人。

"但是," 临走时一个警察对我说,"他们拿走了你的炸鸡,这也实在太不像话了。"

Later, an officer telephoned for additional details. He said the pair’s methods suggested they might be the same men who have committed a number of robberies in the area over the past mouths. He asked me to come to the station and look through the mug shots. So, last mouth I looked through album-sized books of pictures mostly of young men-an amazing number of them actually children.

后来,一个警察打电话来询问另外一些细节。他说这两个劫匪的作案手法表明他们可能就是过去几个月里这一地区多起抢劫案的肇事者。他让我到警察局去看一下疑犯的照片。

于是,上周一我翻看了数本大大小小的照片簿,多数是年轻人的--令人惊讶的是其中有相当一部分实际上还是孩子。

Turning those pages and studying their photographs is like flowing on a sad current, seems to mark in every face, marks of weakness, marks of woe. Together, these young men are a kind of river-one that is out of

control, eating at the foundations of things we hold dear: our freedom to move about, the fruits of our labor, our own lives and those of people we value. Some day, we will have to face this river and seek the depths of his discontent. Presently, all we can do is look at mug shots and stick our fingers in the dam.

一张张翻看并研读这些照片,仿佛漂流在一条让人伤心的河流上,就像身处英国诗人布莱克笔下的泰晤士河畔,似乎"看见每一个过往行人都是满脸饥色,满脸愁苦。"

这些年轻人聚合在一起构成了一条河流--一条已失去控制的河流,这条河流正吞噬着我们所珍视的东西的基础:我们的行动自由;我们的劳动果实;我们的生命,以及那些我们尊敬的人的生命。总有一天,我们将不得不面对这条河流,并探索其对现实不满的深层原因。

而目前,我们所能做的就是看看罪犯的照片,并参与到构筑抑制犯罪的大坝中去。

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2013/12/2四大图谱综合解析[解] 从分子式CHO,求得不饱和度为零,故未知物应为512饱和脂肪族化合物。 1 某未知物分子式为CHO,它的质谱、红外光谱以及核磁共振谱如图,512未知物的红外光谱是在CCl溶液中测定的,样品的CCl稀溶液它的紫外吸收光谱在200 nm以上没有吸收,试确定该化合物结构。44-1的红外光谱在3640cm处有1尖峰,这是游离O H基的特征吸收峰。样品的CCl4浓溶液在3360cm-1处有1宽峰,但当溶液稀释后复又消失,说明存在着分子间氢键。未知物核磁共振谱中δ4. 1处的宽峰,经重水交换后消失。上述事实确定,未知物分子中存在着羟基。未知物核磁共振谱中δ0.9处的单峰,积分值相当3个质子,可看成是连在同一碳原子上的3个甲基。δ3.2处的单峰,积分值相当2个质子,对应1个亚甲基,看来该次甲基在分子中位于特丁基和羟基之间。质谱中从分子离子峰失去质量31(-CHOH)部分而形成基2峰m/e57的事实为上述看法提供了证据,因此,未知物的结构CH是3CCl稀溶液的红外光谱, CCl浓溶液44 CHOH C HC在3360cm-1处有1宽峰23 CH3 2. 某未知物,它的质谱、红外光谱以及核磁共振谱如图,它的根据这一结构式,未知物质谱中的主要碎片离子得到了如下紫外吸收光谱在210nm以上没有吸收,确定此未知物。解释。CH CH3+3.+ +C CH HCOH CHOH C HC3223 m/e31CH CH33 m/e88m/e57-2H -CH-H-CH33m/e29 CH m/e73CHC23+ m/e41 [解] 在未知物的质谱图中最高质荷比131处有1个丰度很小的峰,应从分子量减去这一部分,剩下的质量数是44,仅足以组为分子离子峰,即未知物的分子量为131。由于分子量为奇数,所以未成1个最简单的叔胺基。知物分子含奇数个氮原子。根据未知物的光谱数据中无伯或仲胺、腈、CH3N酞胺、硝基化合物或杂芳环化合物的特征,可假定氮原子以叔胺形式存CH3在。红外光谱中在1748 cm-1处有一强羰基吸收带,在1235 cm-1附近有1典型正好核磁共振谱中δ2. 20处的单峰(6H ),相当于2个连到氮原子上的宽强C-O-C伸缩振动吸收带,可见未知物分子中含有酯基。1040 的甲基。因此,未知物的结构为:-1cm处的吸收带则进一步指出未知物可能是伯醇乙酸酯。O核磁共振谱中δ1.95处的单峰(3H),相当1个甲基。从它的化学位移来CH3N看,很可能与羰基相邻。对于这一点,质谱中,m/e43的碎片离子CHCHCHOC223CH(CHC=O)提供了有力的证据。在核磁共振谱中有2个等面积(2H)的三重33峰,并且它们的裂距相等,相当于AA’XX'系统。有理由认为它们是2个此外,质谱中的基峰m /e 58是胺的特征碎片离子峰,它是由氮原子相连的亚甲-CH-CH,其中去屏蔽较大的亚甲基与酯基上的氧原子22的β位上的碳碳键断裂而生成的。结合其它光谱信息,可定出这个相连。碎片为至此,可知未知物具有下述的部分结构:CHO3NCH2CHCHCHOCCH32231 2013/12/23.某未知物CH的UV、IR、1H NMR、MS谱图及13C NMR数据如下,推[解] 1. 从分子式CH,计算不饱和度Ω=4;11161116导未知物结构。 2. 结构式推导未知物碳谱数据UV:240~275 nm 吸收带具有精细结构,表明化合物为芳烃;序号δc序号δc碳原子碳原子IR ::695、740 cm-1 表明分子中含有单取代苯环;(ppm)个数(ppm)个数MS :m/z 148为分子离子峰,其合理丢失一个碎片,得到m/z 91的苄基离子;1143.01632.01 313C NMR:在(40~10)ppm 的高场区有5个sp杂化碳原子;2128.52731.51 1H NMR:积分高度比表明分子中有1个CH和4个-CH-,其中(1.4~1.2)3128.02822.5132 ppm为2个CH的重叠峰;4125.51910.012因此,此化合物应含有一个苯环和一个CH的烷基。511536.01 1H NMR 谱中各峰裂分情况分析,取代基为正戊基,即化合物的结构为:23

NMR,VU,IR,MS四大图谱解析解析

13C-NMR谱图解析 13C-NMR谱图解析流程 1.分于式的确定 2.由宽带去偶语的谱线数L与分子式中破原子数m比较,判断分子的对称性. 若L=m,每一个碳原子的化学位移都不相同,表示分子没有对称性;若L

基团类型Qc/ppm 烷0-60 炔60-90 烯,芳香环90-160 羰基160 4.组合可能的结构式 在谱线归属明确的基础上,列出所有的结构单元,并合理地组合成一个或几个可能的工作结构。 5.确定结构式 用全部光谱材料和化学位移经验计算公式验证并确定惟一的或

可能性最大的结构式,或与标准谱图和数据表进行核对。经常使用的标准谱图和数据表有: 经验计算参数 1.烷烃及其衍生物的化学位移 一般烷烃灸值可用Lindeman-Adams经验公式近似地计算: ∑ Qc5.2 =nA - + 式中:一2.5为甲烷碳的化学位移九值;A为附加位移参数,列于下表,为具有某同一附加参数的碳原子数。 表2 注:1(3).1(4)为分别与三级碳、四级碳相连的一级碳;2(3)为与三级碳相连的二级碳,依此类推。 取代烷烃的Qc为烷烃的取代基效应位移参数的加和。表4一6给出各种取代基的位移参数

(完整版)2019-2020年中考英语完形填空与阅读理解复习练习Unit7

2019-2020年中考英语完形填空与阅读理解复习练习 Unit 7 PassageA 话题:社会公德词数:243 参考用时:6分钟Have you ever offered a helping hand to those who are in trouble? One day, two ___1___ were walking along the road to school when they saw an old woman carrying a large basket of pears. They thought the woman looked very __2___. They went up to her and said, “Are you going to town? If you are, we will help carry your basket.” “Thank you,” ___3___ the woman, “you are very kind. You see I’m weak and ill.” Then she told them that she was now going to market to __4__the pears which grew on the only tree in her little garden. “We are all going to the __5___.” said the boys. “Let us have the basket.” And they took hold of it, one each side. They walked __6__with the heavy basket, but happily. The other day, I saw a little girl stop and _7__a piece of orange peel (皮), which she threw into the dustbin (垃圾桶), “I wish __8__ would throw that on the sidewalk,” said she. “Someone may step on it and fall.” Perhaps some may say that these are not __9__ things. That is right. But such a little thing shows that you have a thoughtful mind and a feeling heart. We must not wait for the __10_ to do great things. We must begin with little things of love. 1. A. boys B. girls C. men D. women 2. A. bored B. tired C. pleased D. surprised 3. A. asked B. told C. replied D. spoke 4. A. bring B. buy C. take D. sell 5. A. town B. market C. garden D. school 6. A. weakly B. quickly C. slowly D. quietly 7. A. take out B. cut off C. put down D. pick up 8. A. nobody B. everybody C. somebody D. anybody 9. A. little B. good C. great D. bad 10. A. pay B. time C. advice D. love 读后自主学习 【答案速查】参见答案P 【自我评价】我做对了_____题,我很棒!我做错了____题,没关系,再努力! 【答案还原】将正确答案填写到文中空格处。 【诵读全文】大声朗读文章3-4遍、整体感知全文,体悟作者意图。 【我来总结】完成下列学习任务,并加以背诵。 1. 短语互译 (1) offer a helping hand to ________ (2)take hold of _____________ (3) 另外一天__________________ (4)以……开始____________________ 2. 佳句翻译 (1) They went up to her. _______________________________________________________________________ (2) And they took hold of it, one each side.

四大图谱综合解析

2013/12/2
四大图谱综合解析
1 某未知物分子式为C5 H12 O,它的质谱、红外光谱以及核磁共振谱如图,
它的紫外吸收光谱在200 nm以上没有吸收,试确定该化合物结构。
CCl4稀溶液的红外光谱, CCl4浓溶液 在3360cm-1处有1宽峰
[解] 从分子式C5H12O,求得不饱和度为零,故未知物应为 饱和脂肪族化合物。 未知物的红外光谱是在CCl4溶液中测定的,样品的CCl4稀溶液 的红外光谱在3640cm-1处有 1尖峰,这是游离 O H基的特征吸收 峰。样品的CCl4浓溶液在 3360cm-1处有 1宽峰,但当溶液稀释 后复又消失,说明存在着分子间氢键。未知物核磁共振谱中δ4. 1处的宽峰,经重水交换后消失。上述事实确定,未知物分子 中存在着羟基。 未知物核磁共振谱中δ0.9处的单峰,积分值相当3个质子,可 看成是连在同一碳原子上的3个甲基。δ3.2处的单峰,积分值 相当2个质子,对应1个亚甲基,看来该次甲基在分子中位于特 丁基和羟基之间。 质谱中从分子离子峰失去质量31(- CH2 OH)部分而形成基 峰m/e57的事实为上述看法提供了证据,因此,未知物的结构 CH3 是
H3C
C
CH3
CH2OH
根据这一结构式,未知物质谱中的主要碎片离子得到了如下 解释。
CH 3
2. 某未知物,它的质谱、红外光谱以及核磁共振谱如图,它的 紫外吸收光谱在210nm以上没有吸收,确定此未知物。
CH2
+ OH m/e31 -2H
+ . CH2OH
H3C
CH3
H3C
C
CH 3
C+
CH3
m/e88 -CH3 m/e29 m/e73
m/e57 -CH3 -H CH 3 C + CH 2
m/e41
[解] 在未知物的质谱图中最高质荷比131处有1个丰度很小的峰,应 为分子离子峰,即未知物的分子量为131。由于分子量为奇数,所以未 知物分子含奇数个氮原子。根据未知物的光谱数据中无伯或仲胺、腈、 酞胺、硝基化合物或杂芳环化合物的特征,可假定氮原子以叔胺形式存 在。 红外光谱中在1748 cm-1处有一强羰基吸收带,在1235 cm-1附近有1典型 的宽强C-O-C伸缩振动吸收带,可见未知物分子中含有酯基。1040 cm-1处的吸收带则进一步指出未知物可能是伯醇乙酸酯。 核磁共振谱中δ1.95处的单峰(3H),相当1个甲基。从它的化学位移来 看,很可能与羰基相邻。对于这一点,质谱中,m/e43的碎片离子 (CH3C=O)提供了有力的证据。在核磁共振谱中有2个等面积(2H)的三重 峰,并且它们的裂距相等,相当于AA’XX'系统。有理由认为它们是2个 相连的亚甲-CH2-CH2,其中去屏蔽较大的亚甲基与酯基上的氧原子 相连。 至此,可知未知物具有下述的部分结构:
O CH 2 CH 2 O C CH 3
从分子量减去这一部分,剩下的质量数是 44,仅足以组 成1个最简单的叔胺基。
CH 3 CH3 N
正好核磁共振谱中δ2. 20处的单峰(6H ),相当于2个连到氮原子上 的甲基。因此,未知物的结构为:
CH3 CH3 O N CH2 CH2 O C CH3
此外,质谱中的基峰m /e 58是胺的特征碎片离子峰,它是由氮原子 的β位上的碳碳键断裂而生成的。结合其它光谱信息,可定出这个 碎片为
CH3 CH3 N CH 2
1

初中英语知识点总结

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