文档库 最新最全的文档下载
当前位置:文档库 › CCNA Slides Chapter 6

CCNA Slides Chapter 6

Chapter 6 Catalyst Switch Operations

Objectives

Upon completion of this chapter, you will be able to perform the following tasks:?Describe Layer 2 switching (bridging) operations

?Describe the Catalyst 1900 switch operations ?Describe the Catalyst 1900 switch default configuration

?Configure Catalyst 1900 switch

?Use show commands to verify Catalyst 1900 switch configuration and operations

?Address learning ?Forward/filter decision ?

Loop avoidance Three Switch Functions

How Switches Learn Host

Locations

?Initial MAC address table is empty MAC address table

0260.8c01.11110260.8c01.22220260.8c01.3333

0260.8c01.4444

E0E1E2E3A B

C D

How Switches Learn Hosts

Locations

?Station A sends a frame to Station C

?Switch caches station A MAC address to port E0 by learning the source address of data frames

?The frame from station A to station C is flooded out to all

ports except port E0 (unknown unicasts are flooded)

MAC address table 0260.8c01.11110260.8c01.22220260.8c01.3333

0260.8c01.4444

E0: 0260.8c01.1111

E0E1E2E3D

C B

A

How Switches Learn Host

Locations

?Station D sends a frame to station C

?Switch caches station D MAC address to port E3 by learning the source Address of data frames

?The frame from station D to station C is flooded out to all ports except port E3 (unknown unicasts are flooded)MAC address table

0260.8c01.11110260.8c01.22220260.8c01.33330260.8c01.4444

E0: 0260.8c01.1111

E3: 0260.8c01.4444

E0

E1E2E3D

C A B

How Switches Filter Frames

?Station A sends a frame to station C

?Destination is known, frame is not flooded E0: 0260.8c01.1111E2: 0260.8c01.2222E1: 0260.8c01.3333

E3: 0260.8c01.44440260.8c01.11110260.8c01.22220260.8c01.33330260.8c01.4444

E0

E1E2E3X X D

C A B

MAC address table

Broadcast and Multicast

Frames

?Station D sends a broadcast or multicast frame

?Broadcast and multicast frames are flooded to

all ports other than the originating port 0260.8c01.11110260.8c01.22220260.8c01.33330260.8c01.4444

E0

E1E2E3D

C A

B

E0: 0260.8c01.1111E2: 0260.8c01.2222E1: 0260.8c01.3333E3: 0260.8c01.4444MAC address table

Redundant Topology

Server/host X Router Y

Segment 1

Segment 2

?Redundant topology eliminates single points of failure ?Redundant topology causes broadcast storms, multiple frame copies, and MAC address table instability problems

Broadcast Storms

Server/host X Router Y

Segment 1 Broadcast

Switch A Switch B

Segment 2 Host X sends a Broadcast

Broadcast Storms

Server/host X Router Y

Segment 1 Broadcast

Switch A Switch B

Segment 2 Host X sends a Broadcast

Broadcast Storms

Segment 1

Segment 2 Server/host X Router Y

Broadcast

Switches continue to propagate broadcast traffic over and over

Switch A Switch B

Segment 1

Segment 2

Server/host X Router Y

Unicast Switch A Switch B

?Host X sends an unicast frame to router Y

?Router Y MAC address has not been learned by either switch yet

Segment 1Segment 2

Server/host X

Router Y Unicast

Switch A

Switch B ?Host X sends an unicast frame to Router Y

?Router Y MAC Address has not been learned by

either Switch yet

?Router Y will receive two copies of the same frame

Unicast Unicast

Segment 1Segment 2

Server/host X

Router Y Unicast

Unicast Switch A

Switch B ?Host X sends an unicast frame to Router Y

?Router Y MAC Address has not been learned by either Switch yet

?Switch A and B learn Host X MAC address on port 0

Port 0

Port 1Port 0Port 1

Segment 1Segment 2

Server/host X

Router Y Unicast

Unicast Switch A Switch B

?

Host X sends an unicast frame to Router Y ?

Router Y MAC Address has not been learned by either Switch yet ?

Switch A and B learn Host X MAC address on port 0?

Frame to Router Y is flooded ?Switch A and B incorrectly learn Host X MAC address on port 1

Port 0Port 1Port 0

Port 1

?Complex topology can cause multiple loops to occur

?

Layer 2 has no mechanism to stop the loop

Server/host

Workstations

Loop

Loop

Loop

Multiple Loop Problems

Broadcast

Solution: Spanning-Tree Protocol

Provides a loop free redundant network topology by placing certain ports in the blocking state Block

x

Spanning-Tree Operations

?One root bridge per network

?One root port per nonroot bridge

?One designated port per segment

x

Designated port (F)Root port (F)

Designated port (F)Nondesignated port (B)Root bridge Nonroot bridge SW X SW Y

100baseT

10baseT

Switch Y Default priority 32768 (8000 hex)MAC 0c0022222222Switch X

Default priority 32768

(8000 hex)

MAC 0c0011111111Spanning-Tree Protocol

Root Bridge Selection

BPDU

BPDU = Bridge protocol data unit

(default = sent every 2 seconds)

Root bridge = Bridge with the lowest bridge ID

Bridge ID = Bridge priority + bridge MAC address

In the example, which switch has the lowest bridge ID?

相关文档