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EIGRP OSPF Redistribution Sim

July 31st, 2010in LabSim Go to comments

Question: (Hope someone will contribute the detailed requirement of this sim!)

Some information I have gathered so far:

R2 is an ASBR for EIGRP 100 and OSPF AREA 24

R3 is an ASBR for EIGRP 100 and OSPF AREA 34

[note: so there are TWO separate areas on TWO separate ASBRS

thus you need to do redistribution on R2 and R3 // 在R2和R3上做重分发

R1 is ONLY in EIGRP 100, and is THE ONLY router you can ping from. R4 has a loopback interface that must be pinged from R1.

R4 is running OSPF and has redundant(多余的) link to EIGRP network over R3 router.

Notice: You should make a ping from R1 to 172.16.100.1 network to make sure everything is working correctly.

Answer and Explanation:

Thanks to POONAM who send us the topology and configuration. He got 100% on EIGRP-OSPF lab so this solution is perfect! Please say thank to him and others who contribute this lab-sim!

SOLUTION from POONAM

First we need to find out 5 parameters (Bandwidth, Delay, Reliability, Load, MTU) of the

s0/0/0 interface (the interface of R2 connected to R4) for redistribution :

R2#show interface s0/0/0

Write down these 5 parameters, notice that we have to divide the Delay by 10 because its metric unit is tens of microsecond. For example, we get Bandwidth=1544 Kbit, Delay=20000 us, Reliability=255, Load=1, MTU=1500 bytes then we would redistribute as follows:

R2#config terminal

R2(config)#router ospf 1

R2(config-router)#redistribute eigrp 100 metric-type 1 subnets

R2(config-router)#exit

R2(config-router)#router eigrp 100

R2(config-router)#redistribute ospf 1 metric 1544 2000 255 1 1500

(Notice: In fact, these parameters are just used for reference and we can use other parameters with no problem. Also, a candidate said that the simulator didn’t accept the Bandwidth of 1544; in that case, we can use a lower value, like 128.

If the delay is 20000us then we need to divide it by 10, that is 20000 / 10 = 2000)

For R3 we use the show interface fa0/0 to get 5 parameters too

R3#show interface fa0/0

For example we get Bandwidth=10000 Kbit, Delay=1000 us, Reliability=255, Load=1, MTU=1500 bytes

R3#config terminal

R3(config)#router ospf 1

R3(config-router)#redistribute eigrp 100 metric-type 1 subnets

R3(config)#exit

R3(config-router)#router eigrp 100

R3(config-router)#redistribute ospf 1 metric 10000 100 255 1 1500

Finally you should try to “show ip route” to see the 172.16.100.1 network (the network behind R4) in the routing table of R1 and make a ping from R1 to this network.

Maybe the “copy running-config startup-config” command will not work in this lab so don’t worry, just skip it.

WISH U A VERY BEST GUYS………..

GO ROCK…

二、

EIGRP Stub Sim

July 31st, 2010in LabSim Go to comments

Question

By increasing the first distant office, JS manufactures has extended their business. They configured the remote office router (R3) from which they can reach all Corporate subnets. In order to raise network stableness and lower the memory usage and broadband utilization to R3, JS manufactures makes use of route summarization together with the EIGRP Stub Routing feature. Another network engineer is responsible for the implementing of this solution. However, in the process of configuring EIGRP stub routing connectivity with the remote network devices off of R3 has been missing.

Presently JS has configured EIGRP on all routers in the network R2, R3, and R4. Your duty is to find and solve the connectivity failure problem with the remote office router R3. You should then configure route summarization only to the distant office router R3 to complete the task after the problem has been solved.

The success of pings from R4 to the R3 LAN interface proves that the fault has been corrected and the R3 IP routing table only contains two 10.0.0.0 subnets.

Answer and Explanation:

First we have to figure out why R3 and R4 can not communicate with each other. Use the show running-config command on router R3

Notice that R3 is configured as a stub receive-only router. The receive-only keyword will restrict the router from sharing any of its routes with any other router in that EIGRP autonomous system. This keyword will also prevent any type of route from being sent.

Therefore we will remove this command and replace it with the eigrp stub command:

R3#configure terminal

R3(config)#router eigrp 123

R3(config-router)#no eigrp stub receive-only

R3(config-router)#eigrp stub

R3(config-router)#end

Now R3 will send updates containing its connected and summary routes to other routers. Notice that the eigrp stub command equals to the eigrp stub connected summary because the connected and summary options are enabled by default.

Next we will configure router R3 so that it has only 2 subnets of 10.0.0.0 network. Use the show ip route command on R3 to view its routing table

R3#show ip route

Because we want the routing table of R3 only have 2 subnets so we have to summary

sub-networks at the interface which is connected with R3, the s0/0 interface of R4.

There is one interesting thing about the output of the show ip route shown above: the 10.2.3.0/24, which is a directly connected network of R3. We can’t get rid of it in the routing

table no matter what technique we use to summary the networks. Therefore, to make the routing table of R3 has only 2 subnets we have to summary other subnets into one subnet.

In the output if we don’t see the summary line (like 10.0.0.0/8 is a summary…) then we should use the command ip summary-address eigrp 123 10.2.0.0 255.255.0.0 so that all the ping can work well.

In conclusion, we will use the ip summary-address eigrp 123 10.2.0.0 255.255.0.0 at the interface s0/0 of R4 to summary.

R4>enable

R4#configure terminal

R4(config)#interface s0/0

R4(config-if)#ip summary-address eigrp 123 10.2.0.0 255.255.0.0

Now we jump back to R3 and use the show ip route command to verify the effect, the output is shown below:

(But please notice that the ip addresses and the subnet masks in your real exam might be different so you might use different ones to solve this question)

But in your real exam, if you see the line “10.0.0.0/8 is a summary,….Null0″ then you need to summary using the network 10.0.0.0/8 with the command “ip summary-address eigrp 123 10.0.0.0 255.0.0.0″ . This configuration is less optimize than the first but i t summaries into 2 subnets as the question requires (maybe you will not see this case, don’t worry!).

The command “copy running-config startup-config” will not work so try using this command; just skip if it doesn’t work.

三、

OSPF Sim

July 31st, 2010in LabSim Go to comments

Question

OSPF is configured on routers Amani and Lynai c. Amani’s S0/0 interface and Lynaic’s S0/1 interface are in Area 0. Lynaic’s Loopback0 interface is in Area 2.

Your task is to configure the following:

Por tland’s S0/0 interface in Area 1

Amani’s S0/1 interface in Area 1

Use the appropriate mask such that ONLY Portland’s S0/0 and Amnani’s S0/1 could be in Area 1.

Area 1 should not receive any external or inter-area routes (except the default route).

Answer and Explanation:

First, we configure Portland’s S0/0 interface so that it belongs to Area 1. So, we have to find out which sub-network the IP address 192.168.4.5/30 (the IP of interface S0/0 of Portland) belongs to. This address belongs to a subnetwork which has:

Increment: 4 (/30 = 255.255.255.252 or 1111 1111.1111 1111.1111 1111.1111 1100) Network address: 192.168.4.4 (because 4 = 4 * 1 and 4 < 5)

Broadcast address: 192.168.4.7 (because 7 = 4 + 4 – 1) (It is not necessary to find out the broadcast address but we should know it)

The question requires that only Portland’s S0/0 and Amani’s S0/1 could be in Area 1, therefore we must use a wildcard of 0.0.0.3 (this wildcard is equivalent with a subnet mask of /30) so that there are only 2 IP addresses can participate in area 1 (they are 192.168.4.5 & 192.168.4.6). The full command we use here is network 192.168.4.4 0.0.0.3 area 1

The question also requires that “Area 1 should not receive any external or inter-area routes (except the default route)”. Recall that if we don’t want the router to receive external routes, we have to stop LSA Type 5. And if we don’t want to receive inter-area routes, we have to stop LSA Type 3 and Type 4. Therefore we have to configure area 1 as a totally stubby area. For your information, here is the definition of a totally stubby area:

“Totally stubb area– This area does not accept summary LSAs from other areas (types 3 or 4) or external summary LSAs (Type 5). Types 3,4 and 5 LSAs are replaced by the Area Border Router(ABR) with a default router. Totally stubby areas protect internal routers by minimizing the routing table and summarizing everything outside the area with a default route.” (CCNP BSCI Official Exam Certification Guide, Fourth Edition)

In conclusion, we have to configure area 1 as a totally stubby area. We do that by configuring Portland as stub and configuring Amani (ABR router) as a stub + “no-summary”suffix.

+ Configure Portland router as a stub:

Portland#configure terminal

Portland(config)#router ospf 1

Allow network 192.168.4.4/30 to join Area 1, notice that you have to convert subnet mask into wildcard mask:

Portland(config-router)#network 192.168.4.4 0.0.0.3 area 1

Configure Portland as a stub:

Portland(config-router)#area 1 stub

Portland(config-router)#end

Portland#copy running-config startup-config

+ Configure Amani router as a “totally stub”:

Amani#configure terminal

Amani(config)#router ospf 1

Amani(config-router)#network 192.168.4.4 0.0.0.3 area 1

Make area 1 become a totally stubby area, notice that we can only use this command on ABR router:

Amani(config-router)#area 1 stub no-summary

Amani(config-router)#end

Amani#copy running-config startup-config

四、

IPv6 OSPF Virtual Link Sim

July 31st, 2010in LabSim Go to comments

Question

Acme is a small export company that has an existing enterprise network that is running IPv6 OSPFv3. Currently OSPF is configured on all routers. However, R4′s loopback address (FEC0:4:4) cannot be seen in R1′s IPv6 routing table. Y ou are tasked with identifying the cause of this fault and implementing the needed corrective actions that uses OSPF features and does no change the current area assignments. You will know that you have corrected the fault when R4′s loopback address (FEC0:4:4) can be seen in the routing table of R1.

Special Note: To gain the maximum number of points you must remove all incorrect or unneeded configuration statements related to this issue.

Answer and Explanation:

To troubleshoot the problem, first issue the show running-config on all of 4 routers. Pay more attention to the outputs of routers R2 and R3

The output of the “show running-config” command of R2:

The output of the “show running-config” command of R3:

We knew that all areas in an Open Shortest Path First (OSPF) autonomous system must be physically connected to the backbone area (Area 0). In some cases, where this is not possible,we can use a virtual link to connect to the backbone through a non-backbone area. The area through which you configure the virtual link is known as a transit area. In this case, the area 11 will become the transit area. Therefore, routers R2 and R3 must be configured with the area virtual-link command.

+ Configure virtual link on R2 (from the first output above, we learned that the OSPF process ID of R2 is 1):

R2>enable

R2#configure terminal

R2(config)#ipv6 router ospf 1

R2(config-rtr)#area 11 virtual-link 3.3.3.3

(Notice that we have to use neighbor router-id 3.3.3.3, not R2′s router-id 2.2.2.2)

+ Configure virtual link on R3 (from the second output above, we learned that the OSPF process ID of R3 is 1 and we have to disable the wrong configuration of “area 54 virt ual-link 4.4.4.4″):

R3>enable

R3#configure terminal

R3(config)#ipv6 router ospf 1

R3(config-rtr)#no area 54 virtual-link 4.4.4.4

R3(config-rtr)#area 11 virtual-link 2.2.2.2

We should check the configuration on R4:

R4>enable

R4#show running-config

You will see a wrongly configured virtual-link command. To get full mark we have to disable this command:

R4#configure terminal

R4(config)#ipv6 router ospf 1

R4(config-rtr)#no area 54 virtual-link 3.3.3.3

After finishing the configuration don’t forget to ping bet ween R1 and R4 to make sure they work well!

Now all the configuration was done. It is weird that we can’t ping the IPv6 loopback interface of R4 (with the ping or ping ipv6 command) but we can check by using the command show ipv6 route on R1

The copying running-config startup-config command will not work but don’t worry, just skip it.

Notice: If you issue the command “show running-config” on R1, you will see these two lines:

passive-interface default

no passive-interface fa0/0 (fa0/0 is the interface connecting with R2)

These two lines make all the interfaces of R1 become passive interfaces except interface

fa0/0. They are correctly configured so don’t try to disable them.

五、

EIGRP Simlet

July 31st, 2010in ROUTE 642-902Go to comments

EIGRP – SHOW IP EIGRP TOPOLOGY

ALL-LINKS

Here you will find answers to EIGRP Simlet question

Question

Refer to the exhibit. BigBids Incorporated is a worldwide auction provider. The network uses EIGRP as its routing protocol throughout the corporation. The network administrator does not understand the convergence of EIGRP. Using the output of the show ip eigrp topology all-links command, answer the administrator’s questions.

Question 1

Which two networks does the Core1 device have feasible successors for? (Choose two)

A – 172.17.0.0/30

B – 172.17.1.0/24

C – 172.17.2.0/24

D – 172.17.3.0/25

E – 172.17.3.128/25

F – 10.140.0.0/24

Answer: A F

Explanation

To understand the output of the “show ip eigrp topology all-links command” command, let’s analyze an entry (we choose the second entry because it is better for demonstration than the first one)

The first line tells us there is only 1 successor for the path to 10.140.0.0/24 network but there are 2 lines below. So we can deduce that one line is used for successor and the other is used for another route to that network. Each of these two lines has 2 parameters: the first one (“156160″ or “157720″) is the Feasible Distance (FD) and the second (“128256″ or “155160″) is the Advertised Distance (AD) of that rout e.

The next thing we want to know is: if the route via 172.17.10.2 (the last line) would become the feasible successor for the 10.140.0.0/24 network. To figure out, we have to compare the Advertised Distance of that route with the Feasible Distance of the successor’s route, if AD < FD then it will become the feasible successor. In this case, because AD (155160) < FD (156160) so it will become the feasible successor. Therefore we can conclude the network 10.140.0.0/24 has 1 feasible successor.

After understa nding the output, let’s have a look at the entire output:

Because the question asks about feasible successor so we just need to focus on entries which have more paths than the number of successor. In this case, we find 3 entries that are in blue boxes because they have only 1 successor but has 2 paths, so the last path can be the feasible successor.

By comparing the value of A D (of that route) with the FD (of successor’s route) we figure out there are 2 entries will have the feasible successor: the first and the second entry. The third entry has AD = FD (30720) so we eliminate it.

Question 2

Which three EIGRP routes will be installed for the 172.17.3.128/25 and 172.17.2.0/24 networks? (Choose three)

A – 172.17.3.128.25 [90/28160] via 172.17.1 2, 01:26:35, FastEthernet0/2

B – 172.17.3.128/25 [90/30720] via 172.17.3.2, 01:26:35. FastEthemet0/3

C – 172.17.3.128/25 [90/30720] via 172.17.10.2, 01:26:35. FastEthernet0/1

D – 172.17.2.0/24 [90/30720] via 172.17.10.2, 02:10:11, FastEthernet0/1

E – 172.17.2.0/24 [90/28160] via 172.17.10.2, 02:10:11. FastEthernet0/1

F – 172.17.2.0/24 [90/33280] via 172.17.3.2, 02:10:11. FastEthernet0/3

Answer: B C D

First indicate the positions of these networks:

Network 172.17.3.128/25 has 2 successors, therefore the two paths below are both successors.

Network 172.17.2.0/24 has only 1 successor, therefore the path lies right under it is the successor.

Question 3

Which three networks is the router at 172.17.10.2 directly connected to? (Choose three)

A – 172.17.0.0/30

B – 172.17.1.0/24

C – 172.17.2.0/24

D – 172.17.3.0/25

E – 172.17.3.128/25

F – 172.17.10.0/24

Answer: C E F

First, we should notice about the entry in the orange box, it shows that the network

172.17.10.0/24 is directly connected with this router and has a FD of 28160. So we can guess the networks that directly connected with router at 172.17.10.2 will be shown with an AD of 28160. From that, we find out 3 networks which are directly connected to the router at 172.17.10.2 (they are green underlined). The network 172.17.10.0/24 is surely directly connected to the router at 172.17.10.2 (in fact it is the network that links the router at 172.17.10.2 with Core1 router).

六、

Policy Based Routing Sim

July 31st, 2010in LabSim Go to comments

Question

Company Acan has two links which can take it to the Internet. The company policy demands that you use web traffic to be forwarded only to Frame Relay link if available and other traffic can go through any links. No static or default routing is allowed.

Answer and Explanation:

Notice: The answer and explanation below are from PeterPan and Helper.Please say thank to them!

All the HTTP traffic from the EIGRP Network should go through Frame Relay link if available and all the other traffic should go through either link.

The only router you are able to administrate is the Border Router, from the EIGRP Network you may only send HTTP traffic. As the other people mentioned, actually it is not a BGP lab. You are not able to execute the c ommand “router bgp 65001″

1) Access list that catches the HTTP traffic:

BorderRouter#access-list 101 permit tcp any any eq www

Note that the server was not directly connected to the Border Router. There were a lot of EIGRP routes on it. In the real exam you do not know the exact IP address of the server in the EIGRP network so we have to use the source as “any” to catch all the source addresses.

2) Route map that sets the next hop address to be ISP1 and permits the rest of the traffic:

BorderRouter(config)#route-map pbr permit 10

BorderRouter(config-route-map)#match ip address 101

BorderRouter(config-route-map)#set ip next-hop 10.1.101.1

BorderRouter(config-route-map)#exit

BorderRouter(config)#route-map pbr permit 20

(Notice: the route-map pbr permit 20 line allows other traffic than HTTP to be routed. Otherwise, other traffic will be dropped)

3) Apply the route-map on the interface to the server in the EIGRP Network: BorderRouter(config-route-map)#exit

BorderRouter(config)#int fa0/0

BorderRouter(config-if)#ip policy route-map pbr

BorderRouter(config-if)#exit

BorderRouter(config)#exit

4) There is a “Host for Testing”, click on this host to open a box in which there is a button named “Generate HTTP traffic”. Click on this button to generate some packets for HTT P traffic. Jump back to the BorderRouter and type the command “show route-map”.

BorderRouter#show route-map

In the output you will see the line “Policy routing matches: 9 packets…”. It means that the route-map we configured is working properly.

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