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地下室抗浮底板计算书(解锁板)

地下室抗浮底板计算书(解锁板)
地下室抗浮底板计算书(解锁板)

说明:采用修正经验系数法,按大柱帽无梁筏板计算。

混凝土标号:C30 2.01N/mm 2

底板板厚 h = 450mm 1.43N/mm 2承台厚 h =

1000mm

柱尺寸 a X b =

0.6

X

0.6

m

柱距:Lx X Ly (m) =

8X 8

m 承台尺寸A X B = 1.4X 1.4m

迎水筋保护层 C = 50mm 水位高于底板面4m

背水钢筋保护层 C =

20mm 2.5KN/m 2

计算裂缝 C =

25mm

30.8KN/m 2

(扣除向下恒载)

㈠.X向柱上板带承台边支座截面负弯矩计算:沿X向总弯矩标准值:

Mox=qLy(Lx-C)2/8 =30.8*8*(8-1.4)^2/8=

1341.6KN*m 0.5*1341.6/(8/2)=KN*m

1.强度计算:

底板底筋 fy =

360N/mm 2

ho=mm

①④号筋每延米筋面积 As= 1.2*167.7/(0.9*360*392)=1584.5mm 2实配φ

16@75

实配 As =2679mm 2

满足要求!

2.裂缝验算:

构件受力特征系数 α

cr =

2.1

(按砼规表8.1.2-1取)钢筋弹性模量 Es=N/mm 2

(按砼规表4.2.4取)

σ

sk =M k /(0.87hoA s)=

167.7/(0.87*392*2679)=

N/mm 2

地下室底板抗水板计算

二.计算过程:

一.基本资料:

0.002

3921.2Mx/(0.9fyho)=

柱上板带每延米弯矩 Mx = 0.5Mox/By=最小配筋率 ρ

min =

167.7

混凝土强度标准值f tk =183.6

2.1E+05

混凝土强度设计值f t =垫层重水净反力 q=实际配筋率 ρ=

0.00595

ρte =As/(0.5bh)=2679/(0.5*1000*450)=>0.010.0121.1-0.65*2.01/(0.012*183.6)=

(0.2<ψ<1.0)

取ψ=0.507

2.1*0.507*18

3.6*(1.9*25+0.08*16/0.012)/210000

=0.144mm

<

0.2

mm 满足要求!

㈡.X向柱上板带跨中弯矩及跨中板带弯矩计算:

1. 沿X向总弯矩标准值:

Mox=qLy(Lx-2C/3)2/8=30.8*8*(8-2*1.4/3)^2/8=KN*m a.柱上板带跨中每延米Mx=0.18*1538/(8/2)=KN*m

ψ=0.2

承台底板底筋 fy =

360N/mm 2

ho=mm

承台每延米筋面积 As= 1.2*602.4/(0.9*360*942)=2368.5mm 2实配φ

16@75

实配 A s =2679mm 2

满足要求!

2.裂缝验算:

构件受力特征系数 α

cr =

2.1

(按砼规表8.1.2-1取)钢筋弹性模量 Es=N/mm 2

(按砼规表4.2.4取)

σ

sk =M k /(0.87hoAs)=

602.4/(0.87*942*2679)=N/mm 2ρte =As/(0.5bh)=

2679/(0.5*1000*1000)=

<0.010.011.1-0.65*2.01/(0.01*274.4)=

(0.2<ψ<1.0)

取ψ=0.624

2.1*0.624*274.4*(1.9*25+0.08*16/0.01)/210000

=0.301mm

<

0.301

mm 满足要求!

㈣.Y向柱上板带承台边支座截面负弯矩计算:

沿Y向总弯矩标准值:

Moy=qLx(Ly-C)2/8 =30.8*8*(8-1.4)^2/8=

1341.6KN*m

0.5*1341.6/(8/2)=

KN*m

1.强度计算:

ωmax =α

cr ψ

σsk (1.9c+0.08d eq /ρte )/Es=

最小配筋率 ρ

min =

ψ=1.1-0.65f tk /(ρ

te σsk )=

柱上板带每延米弯矩 My = 0.5Moy/Bx=ωmax =α

cr ψ

σsk (1.9C+0.08d eq /ρte )/Es=

0.18Mox/By=1.2Mx/(0.9fyho)=

167.7

0.002

0.0120.507

153869.2 取ρ

te =

ψ=1.1-0.65f tk /(ρ

te σsk )=

0.624

实际配筋率 ρ= 0.002682.1E+05

274.4 取ρ

te =

0.005

942

底板底筋 fy =

360N/mm 2

ho=mm

②⑥号筋每延米筋面积 As= 1.2*167.7/(0.9*360*392)=1584.5mm 2实配φ

16@75

实配 As =2679mm 2

满足要求!

2.裂缝验算:

构件受力特征系数 α

cr =

2.1

(按砼规表8.1.2-1取)钢筋弹性模量 Es=N/mm 2

(按砼规表4.2.4取)

σ

sk =M k /(0.87hoA s)=

167.7/(0.87*392*2679)=N/mm 2ρte =As/(0.5bh)=

2679/(0.5*1000*450)=

>0.010.0121.1-0.65*2.01/(0.012*183.6)=

(0.2<ψ<1.0)

取ψ=0.507

2.1*0.507*18

3.6*(1.9*25+0.08*16/0.012)/210000

=0.144mm

<

0.2

mm 满足要求!

㈤.Y向柱上板带跨中弯矩及跨中板带弯矩计算:

1. 沿Y向总弯矩标准值:

Moy=qLx(Ly-2C/3)2/8=30.8*8*(8-2*1.4/3)^2/8=KN*m a.柱上板带跨中每延米My=0.18*1538/(8/2)=KN*m b.跨中板带支座每延米My=0.17*1538/(8/2)=KN*m c.跨中板带跨中每延米My=0.15*1538/(8/2)=KN*m

My=

69.2KN*m 1.强度计算:

底板面筋 fy =

360N/mm 2

ho=

mm

⑤号筋每延米筋面积As=1.2My/(0.9fyho)=

1.2*69.2/(0.9*360*422)=607mm 2实配φ

16@150

实配 As =1340mm 2

满足要求!

2.裂缝验算:

构件受力特征系数 α

cr =

2.1

(按砼规表8.1.2-1取)钢筋弹性模量 Es=N/mm 2

(按砼规表4.2.4取)σ

sk =M k /(0.87hoAs)=

69.2/(0.87*422*1340)=N/mm 2ρte =As/(0.5bh)=

1340/(0.5*1000*450)=

<0.01取ρ

te =0.011.1-0.65*2.01/(0.01*140.7)=

<0.2

取ψ=0.2

2.1*0.2*140.7*(1.9*20+0.08*16/0.01)/210000

=0.047mm

<0.2

mm 满足要求!㈥.Y向承台根部负弯矩计算:沿Y向总弯矩标准值:

Lx/2=

4>

1.4

1.4Moy=qLx(Ly-C)2/8 =30.8*8*(8-0.6)^2/8=

KN*m 0.5*1686.6/1.4=

KN*m

1.强度计算:

承台底板底筋 fy =

360N/mm 2

ho=mm

承台每延米筋面积 As= 1.2*602.4/(0.9*360*942)=2368.5mm 2实配φ

16@75

实配 As =2679mm 2

满足要求!

2.裂缝验算:

构件受力特征系数 α

cr =

2.1

(按砼规表8.1.2-1取)钢筋弹性模量 Es=N/mm 2

(按砼规表4.2.4取)

σ

sk =M k /(0.87hoAs)=

602.4/(0.87*942*2679)=N/mm 2ρte =As/(0.5bh)=

2679/(0.5*1000*1000)=

<0.01

0.01

1.2My/(0.9fyho)=

最小配筋率 ρ

min =

0.002

3920.012

取ρ

te =

ψ=1.1-0.65f tk /(ρ

te σsk )=

0.507

实际配筋率 ρ= 0.005952.1E+05

183.60.17Moy/Bx=65.40.15Moy/Bx=

57.7

ωmax =α

cr ψ

σsk (1.9C+0.08deq/ρte )/Es=

15380.18Moy/Bx=69.2实际配筋率 ρ= 0.00298

0.006

2.1E+05

140.7底板面筋计算弯矩选用

422

最小配筋率 ρ

min =

0.002

实际配筋率 ρ= ψ=1.1-0.65f tk /(ρ

te σsk )=

0.171

ωmax =α

cr ψ

σsk (1.9C+0.08d eq /ρte )/Es=

0.00268取 Bx=

1686.6

1.2My/(0.9fyho)=

承台每延米弯矩 My = 0.5Moy/Bx=602.4

取ρ

te =

274.4942

0.005

最小配筋率 ρ

min =

2.1E+05

0.002

1.1-0.65*

2.01/(0.01*274.4)=

(0.2<ψ<1.0)取ψ=0.624

2.1*0.624*274.4*(1.9*25+0.08*16/0.01)/210000

=0.301mm

<

0.301

mm 满足要求!

ωmax =α

cr ψ

σsk (1.9C+0.08d eq /ρte )/Es=

ψ=1.1-0.65f tk /(ρte σsk )=

0.624

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