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湖南省长郡中学2019-2020学年高二上学期入学考试英语试题

湖南省长郡中学2019-2020学年高二上学期入学考试英语试题
湖南省长郡中学2019-2020学年高二上学期入学考试英语试题

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第一部分:单项填空(15分) 21._________the examination will _________ easy. A. Hopeful; become B. Hopefully; turn out C. Be hoped; turn out to be D. Hoping; turn 22._________ we know, Tom is sure to succeed in this competition. A. So long as B. So far as C. So that D. Now that 23.I can hardly imagine Peter _________ across the Atlantic Ocean in five days. A. sail B. to sail C. sailing D. to have sailed 24.He _________ a good example _________ everyone _________ getting up early. A. gives; for; at B. gave; to; with C. sets; to; by D. set; for; in 25.On the ground _________, who was crying. A. a little boy lay B. a little boy lies C. did the little boy lie D. lay a little boy 26.He demanded that he _________ the place at once. A. leave B. leaves C. left D. will leave 27. The little girl couldn't work the problem out.She wasn't ___________ clever. A.that B.much C.many D.too 28.It _________ be Jack who broke the windows. It _________ be

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湖南省长沙市长郡中学2016-2017学年高一下学期期末考试物理试题

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C、它只能在赤道的正上方,但离地心的距离可按需要选择不同值 D、它只能在赤道的正上方,且离地心的距离是一定的 6.如图所示,a、b、c是一条电场线上的三点,电场线的方向由 a到 c,a、b间的距离等于 b、c间的距离,用φa、φb、φc和 E a、E b、E c分别表示 a、b、c三点的电势和电场强度,可以判定 A. φa>φb>φc B. Eα>E b>E c C. φa-φb=φb-φc D. Eα=E b=E c 7.一宇宙飞船绕地球做匀速圆周运动,飞船原来的线速度是 v1,周期是 T1,假设在某时刻它向后喷气做加速运动后,进入新轨道做匀速圆周运动,运动的线速度是 v2,周期是 T2,则 A. v1>v2,T1>T2 B. v1>v2,T1T2 D. v1

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湖南省长沙市长郡中学2016-2017学年高二上学期期末考试英语试题(有答案)

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湖南省长郡中学2018-2019学年高二上学期入学考试物理试题

长郡中学2018-2019学年度第二第一学期入学考试 物理 一、选择题(本题包括12小题,每小题4分,共48分,每小题给出的四个选项中,1~8题只有一个选项正确,9~12题有多个选项正确,全部选对的得4分,选对但不全的得2分,有选错的得0分) 1.一质点沿轴正方向做直线运动,通过坐标原点时开始计时,其的图象如图所示,则() A. 质点做匀速直线运动,速度为0.5m/s B. 质点做匀加速直线运动,加速度为0.5m/s2 C. 质点在第1s内的平均速度0.75m/s D. 质点在1s末速度为1.5m/s 【答案】D 【解析】 【详解】由图得:=0.5+0.5t。根据匀变速直线运动的位移公式x=v0t+at2,得:=v0+at,对比可得:v0=0.5m/s,a=1m/s2,则质点做初速度为0.5m/s、加速度为a=1m/s2的匀加速直线运动,故AB错误;质点在第1s末速度为:v=v0+at=0.5+1=1.5m/s。则质点在第1s内的平均速度为:,故C错误,D正确;故选D。 【点睛】本题的实质上是速度-时间图象的应用,关键要运用数学知识得到函数式,分析质点的运动性质,再根据图象读取有用信息. 2.一质点做匀加速直线运动时,速度变化Δv时发生位移x1,紧接着速度变化同样的Δv时发生位移x2,则该质点的加速度为( ) A. B. C. D. 【答案】D 【解析】

【分析】 根据匀变速直线运动的速度位移公式,结合两段过程中速度的变化量相等,联立求出质点的加速度. 【详解】设匀加速的加速度a,物体的速度分别为v1、v2和v3;据运动学公式可知,v22?v12=2ax1,v32?v22=2ax2,且v2-v1=v3-v2=△v;联立以上三式解得:a=。故选D。 3.如图所示为两个等量点电荷的电场线,图中A点和B点、C点和D点皆关于两电荷连线的中点O对称,若将一电荷放在此电场中,则以下说法正确的是() A. 电荷在O点受力最大 B. 电荷沿直线由A到B的过程中,电场力先增大后减小 C. 电荷沿直线由A到B的过程中,电势能先增大后减小 D. 电荷沿直线由C到D的过程中,电场力先增大后减小 【答案】D 【解析】 试题分析:根据电场线的疏密特点,在AB直线上,O点电场强度最小,则受到电场力最小,而在CD直线上,O点的电场强度最大,则受到电场力最大,因此电荷在0点受力不是最大,故A错误.根据电场线的疏密可知,从A到B的过程中,电场强度先减小后增大,则电场力也先减小后增大;同理从C到D的过程中,电场强度先增大后减小,则电场力也先增大后减小.故B错误,D正确,电荷沿直线由A到B的过程中,无法确定电荷做功的正负,因此无法确定电势能变化,故C错误.故选D。 考点:电场线;电场强度 【名师点睛】常见电场的电场线分布及等势面的分布要求我们能熟练掌握,并要注意依据电场线的疏密来判定电场强度的大小,同时注意等量异号电荷形成电场的对称性.加强基础知识的学习,掌握住电场线的特点,即可解决本题。 4.如图所示,在光滑绝缘水平面上的M、N两点各放有一个电荷量分别为+q和+2q的完全相同的金属A、B.在某时刻,使 A、B 以相等的初动能 E 开始沿同一直线相向运动(设这时它们

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