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中考有关CuO还原

中考有关CuO还原
中考有关CuO还原

07年杭州中考卷:(氢气还原氧化铜) 31.(8分)某学生利用下图所示的装置,要测定含杂质(杂质不参加反应)的氧化铜的质量分数。

请回答下列问题:

(1)为保证实验安全,在点燃酒精灯前一步的实验步骤是▲ (2)不.应.

选择▲组的实验数据来计算样品中的氧化铜的质量分数, 原因是▲。

(3)若要使两组数据计算得到的结果一样,应将D 装置连接在上图 中的▲位置(用装置编号表示),并请在D

装置上画出用导管连接的方式,

并标出

D

中的液体名称。

2010年杭州中考卷:(氢气还原氧化铜)

38.(7分)在氢气还原氧化铜的实验中,向50克氧化铜粉末中通氢气,加热一段时间后,测得固体质量减少了8克。求: (1)、已反应掉的氧化铜质量。(列式计算)

(2)、若实验时用的氢气,是用右图标签所示的浓硫酸稀释成稀硫酸后和足量的锌粒反应制取的。取用浓硫酸50毫升,小心加入到300毫升水中稀释,稀释后硫酸溶液的溶质质量分数为

西湖区2009学年第一学期九年级期末教学质量抽测调研科学

18.某气体可能含有水蒸气、CO 、H 2中的一种或几种。为了确定其成分,最佳的实验方案是将气体依次通过装置

A .甲、乙、丙

B .丙、乙、甲

C .丙、甲、乙、丙

D .丙、甲、丙、乙

澄清石灰水

甲乙丙

2011年杭州市各类高中招生文化考试——科学(1)(氢气还原氧化铜,引申到C还原氧化铁)

2009年赤峰市中考化学试题

三、实验题(共19分)

22、(4分)某校在做CO还原CuO的实验时,各小组分别设计了以下四套实验装置。

请你从防止空气污染、节约能源的角度分析:最不理想的实验装置是,最合理的实验装置是。

24、(9分)某实验小组将洁净的铁钉投入到氯化铜溶液中,发现铁钉表面生成红色固体物

质的同时有较多气泡产生,生成的气体是什么呢?

【提出猜想】从物质组成的元素角度分析,产生的气体可能是HCl、Cl2、O2、H2。

【查阅资料】25℃时:HCl气体在水中的溶解度是500,极易溶于水;Cl2在水中的溶解度约是2,易溶于水,它能与NaOH溶液发生化学反应。

【讨论分析】依据猜想和资料,实验小组的同学进行了如下讨论:

(1)甲同学根据资料推理得出产生的气体不可能是。

(2)乙同学认为是O2,则检验O2的方法是

(3)丙同学认为是Cl2,则只需将产生的气体通入盛有NaOH溶液的洗气瓶中,称量通气前后洗气瓶的质量进行检验。Cl2与NaOH溶液反应的化学方程式是:

Cl2+2NaOH=NACl+NaClO+X,则X的化学式是。

【设计方案】实验小组的同学合作设计了如下的试验方案,排除和验证猜想的气体。

①如果产生的气体是O2和H2,你认为装置C中存在的安全隐患是。

②丁同学认为:为确保安全,实验前应先收集一试管气体,用拇指

,若没有听到

,方可采用上面的装置进行实验。

【验证实验】经丁同学确认安全后,小组同学首先对装置A进行称量,再将收集到的干燥的气体从a处通入,过一会儿点燃C处的酒精灯,过一段时间后,发现

表面含CuO的铜网变为光亮的红色;停止通气,再称量装置A,发现质量

无增减。

【实验结论】铁钉与氯化铜溶液反应时,产生的气体是。

【实验反思】(1)装置B中浓H2SO4起作用。

(2)由上述实验可以推出氯化铜溶液显(填“酸性”、“碱性”或“中性”)

2009年汕头中考卷:(C还原氧化铜)

16.为确定木炭还原氧化铜后的固体成份,请你与兴趣小组的同学完成以下探究。

【对固体猜想】

猜想I:全部是金属铜;猜想Ⅱ:除铜外,还含有氧化铜;

猜想Ⅲ:除铜外,还含有木炭;猜想Ⅳ:除铜外,还含有氧化铜、。

【进行实验】实验流程见下图:

【问题与讨论】

A B C D 2 (1)步骤②包括溶解、两步操作,它们共同用到的玻璃仪器是烧杯、。

(2)C 的化学式为,D 的化学式为,由此推出固体B 中含有(写化学式),步骤④发生反应的化学方程式为。

(3)结合(2)的结论推断:如果溶液A 显蓝色,则溶液A 的溶质的化学式为,说明样品 中含有,则证明猜想成立;如果溶液A 无色,则证明猜想成立。

松江区2009学年度第二学期初三5月考:(一氧化碳还原氧化铜) 51.下图表示单质A 所能发生的一系列变化。其中B 、D 为红色(或红棕色)固体;E 为黑色固

体。

请回答下列问题:

(1)请写出下列物质的化学式:A 、E 。

(2)写出⑤中反应的现象_____________________________________ (3)写出下列反应的化学方程式:②;

④。

53. 现有CO 2和CO 组成的混合气体,请回答

①请组装一套装置,能验证出混合气体中的CO 2和CO ,则需要连接的仪器顺序为。(装置可重复使用)

杭州市2011年科学中考模拟试卷:(C 还原氧化铜)

33.某课外活动小组的同学将16克氧化铜和过量的炭粉均匀混合,用下图所示装置进行实验。图中铁架台等装置已略去。请回答有关问题: (1)实验中最多能得到铜克。

(2)同学们想通过测定消耗碳、氧元素的质量和生成二氧化碳的质量,以进一步分析氧化铜和炭粉反应产生的气体除CO 2外是否还有其它产物。反应一段时间后停止加热,冷却到室温。反应前.后测得的数据如下:

分析数据发现,反应中消耗碳和氧元素的质量

(填“大于”或“小于”或“等于”生成二氧

化碳的质量。下列4项中跟这一结果有关的有哪几项?。(填编号) A .装置中还有一部分CO 2未被NaOH 溶液吸收 B .氧化铜和炭粉反应产生的气体除CO 2外还有CO C .氧化铜和炭粉没有完全反应 D .该反应不符合质量守恒定律

(3)有同学认为用图示装置C 代替上面的装置A ,加热前先通一会

气体X ,停止加热后再通一会该气体,这样可使实验测得的数据更能准确的说明问题。你认为在O 2.N 2和H 2三种气体中,X 应选择哪一种气体?。

浙江省杭州市文澜中学2011年5月中考科学模拟试卷 31.(6分)某化学课题小组通过查阅资料得知:固体草酸(H 2C 2O 4·2H 2O )受热可分解,其化学方程式(H 2C 2O 4·2H 2O =CO ↑+CO 2↑+3H 2O )该课题小组的同学在实验室分别进行了如下实验,请回答下列问题:

(1)甲同学利用如图装置制取并收集CO : B 装置的作用 ▲ 。 (2)若要确定C 中搜集的气体中有没有CO 2,应该在下图中气体通入C 装置之前添加一个盛有▲ 的检验装置?

(3)乙同学为了验证草酸的分解产物,设计了四个方案,分别将混合气体(包括水蒸气)依次通过足量 的下列试剂:你认为其中正确的方案是 ▲ _。

A .石灰水、灼热的氧化铜、无水硫酸铜、氢氧化钠溶液

B .无水硫酸铜、氢氧化钠溶液、灼热的氧化铜、石灰水

C .石灰水、无水硫酸铜、灼热的氧化铜、石灰水

D .无水硫酸铜、石灰水、灼热的氧化铜、石灰水

2009年江苏泰安中考卷

22.(4分)按要求写出下列反应的化学方程式: (1)一氧化碳通过加热的氧化铜▲ ;

2010年上海中考卷:

52.下图是利用CO、CO2混合气体中的CO还原CuO的实验示意图。

①仪器a的名称是___________。乙装置中应该用酒精灯的_______焰加热。

②写出甲中反应的化学方程式:_____________________________________;

乙装置的仪器b中黑色粉末变红时发生反应的化学方程式:_____________________。

③反应过程中,丙中可观察到的实验现象是____________________________________。

④该装置存在的主要问题是__________________________________________________。

⑤实验结束后,要从甲装置的混合溶液中回收得到较纯净的NaOH固体。

资料显示,在不同温度下NaOH的溶解度如下:

利用实验室的试剂和条件,实验步骤如下(其中Ⅰ、Ⅱ、Ⅲ为实验操作):

请具体填写试剂A的化学式以及实验操作Ⅰ、Ⅱ、Ⅲ的名称。

化学式:A_____________________;

操作名称:Ⅰ__________________ Ⅱ____________________ Ⅲ__________________。2009年上海中考模拟卷

42、利用下图装置可进行气体性质的探究实验。甲的玻璃管中盛放黑色粉末(CuO 或C ),

乙的洗气瓶中盛放无色溶液(澄清石灰水或NaOH 溶液)。

(1)写出仪器的名称:a ________________,b ________________ (2)根据要求填表:

(3)上述两实验中,在导管c 的尖嘴处都用火柴点燃,其目的是否完全相同?简述理由。

__________________________________________________________________________ 2010年浙教版中考模拟卷10 31.(原创)(6分)实验室采取两种方法制取铜,现有铁,氧化铜,稀硫酸3种物质及下列实验装置。

(1)实验过程中,有蓝色溶液产生的方法(第1种方法)应选用上述装置中的▲。 (填序号)

(2)另一种(第2种方法)的原理是(用化学方程式表示)▲ ▲。

气体

(3)在第1种方法制取的铜中,对可能存在的杂质,可以加▲除去;在第2种方法的过程中,为确保安全,必须要检验▲。

(4)玻璃棒在上述实验中的作用有▲。

2010年浙教版中考模拟卷8

25.(6分)某同学为了探究木炭还原氧化铜所生成的气体产物是什么,提出了猜想:

a.可能是二氧化碳;

b.可能是一氧化碳。

并设计如图所示装置进行实验,预期的实验现象及结论如下:

①若澄清的石灰水变浑浊,则气体为二氧化碳;

②若澄清的石灰水不变浑浊,则气体为一氧化碳。

请你回答:

⑴写出木炭还原氧化铜生成二氧化碳的反应方程式▲;

⑵该同学的猜想是否严谨?若不严谨,请作补充。▲;

⑶请你从环境保护的角度对该实验装置予以评价。▲。

2010年浙教版中考模拟卷11

32.(7分)在实验探究课上,老师给了同学们一包红色粉未,该粉末是铜粉和和氧化铁粉中的一种或两种。同学们为了确定该粉末的成分,进行如下探究。请你参与他们的探究并回答问题。

(1)【提出问题】假设l:红色粉末是铜粉;假设2:红色粉末是氧化铁粉;

假设3:红色粉末是铜粉和和氧化铁粉的混合物。

(2)【设计实验方案】同学们对实验作了如下设

想和分析:取少量红色粉末放入硬质玻璃管中,

通入一氧化碳片刻后加热至充分反应(实验装置

图如下)。

(3)【进行实验】通过实验,根据实验现象

进行分析,确认假设3成立。

(4)【反思与评价】

①实验过程中,硬质玻璃管内发生的化学反应方程式是▲。

②实验时通入一氧化碳片刻后再加热的原因是▲。

③上面的实验装置有不足之处,请你对该装置进行改进,具体措施是▲。

2010年浙教版中考模拟卷13

33、(本题6分)据报道,我国将推广“车用乙醇汽油”技术。乙醇(化学式为C2H5OH)完全燃烧时,生成CO2和H2O;乙醇燃烧时如果氧气不足,还有CO生成。现有装置(如图所示):试用上述装置设计一实验,验证乙醇不完全燃烧的产物中含有CO、CO2、H2O 3种气体。应将乙醇燃烧的产物依次通过(填装置序号,可以重复,没有必要的可以不选)

▲→_▲→▲→▲→▲→▲,最后还要进行尾气处理。

2009年上海中考卷

53.为了探究氧化铜与碳反应生成的气体产物,甲同学设计并进行了如下实验:取一定量氧化铜和碳的混合粉末,在不含氧气的高温条件下反应,将生成的气体通入澄清石灰水,发现石灰水变浑浊。由此得出结论,生成的气体产物一定是CO2。

①甲同学加热混合粉末时观察到的现象是:黑色粉末(5)。

②澄清石灰水变浑浊时发生反应的化学方程式是(6)。

③检验气体产物是CO2的另一种方法是:将生成的气体通入石蕊溶液中,溶液变(7)色。

④乙同学认为,甲同学的实验不能证明反应的气体产物只有CO2,乙同学推测气体产物中可能还有CO。请你从下列A、B、C中选择实验装置,用于验证乙同学的推测。将所选装置的编号填入方框,并在方括号内写出相应装置内盛放的化学试剂。

2009年南京中考题:由还原CuO引申到还原氧化铁

3.一碳化学是以分子中只含有一个碳原子的化合物(如CO、CH4等)为原料来合成一系列化工原料和燃料的化学。CO是从煤的气化或合成气得到的。

(1)煤的气化主要反应有:①2C+O2=2CO ②C+H2O=CO+H2③CO+H2O=CO2+H2

上述反应属于化合反应的是(填序号),属于氧化反应的是(填序号)。

(2)合成气可通过天然气的重整得到,如CH4+H2O=CO+3H2合成气可制二甲醚,二甲醚被称为21世纪的新型燃料。合成气还可用于冶炼金属,用它冶炼铁的部分生产过程示意如下:

①二甲醚(CH3OCH3)可由合成气(CO和H2)在一定的条件下制的。用合成气制二甲醚时,还产生了一种可参与大气循环的、常温为液态的氧化物,写出该反应的化学方程式:

②合成气在冶炼铁的生产过程中所起的作用是。

(3)化学兴趣小组的同学为了测定某赤铁矿石中氧化铁的质量分数。

Ⅰ.甲同学取一定质量的赤铁矿粉与过量的木炭粉混合后,用下图所示装置以合理的操作步骤测定(假设杂质始终不发生变化)。

①实验中持续通入干燥的氮气。加热前缓缓通入一段时间,其作用是。

②停止加热前是否需要先断开a和b的连接处以防止倒吸?为什么?

③如果氢氧化钠溶液对二氧化碳的吸收是完全的,那么甲同学用氢氧化钠溶液的质最变化测定出氧化铁的质量分数将(选填“偏大”、“偏小”或“准确”),原因是。

Ⅱ.乙同学取矿石样品10g,加入足量稀盐酸,完全反应后,共用去稀盐酸109.5g 过滤得到滤渣2 g(假设杂质既不溶于水也不与酸发生反应)。请你和乙同学—起计算赤铁矿石中氧化铁的质量分数和反应后溶液中溶质的质量分数。(请写出计算过程)。

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【英语】中考英语阅读理解经典题型带答案 一、初三英语阅读理解(含答案详细解析) 1.根据短文理解,选择正确答案。 A Some people think only school children do not agree with their parents, however, it is not true. Communication is a problem for parents and children of all ages. If it's hard for you to communicate with your parents, don't worry about it. Here are some suggestions for you to bridge generation gap(代沟). Don't argue with your parents. Don't get to your parents when you are angry. Your parents probably won't consider your ideas if you are shouting at them You can't express(表达)yourself well if you are angry. Go to some place to cool off. Make sure you understand why you are unhappy. Then think about what you want to say to your parents. If you don't think you can speak to them at the moment, try writing a letter. Try to reach a compromise (和解). Perhaps you and your parents disagree(有分歧) on something. You can keep your disagreement and try your best to accept each other. Michael's mother didn't agree with him about buying a car. They argued over it, but finally they came to a compromise. Michael bought the car, but only drove it on certain days. Of course your parents might refuse to compromise on something. In these situations, it is especially important to show love and respect (尊敬) to them. Showing respect will keep your relationship strong. Talk about your values. The values of your parents are probably different from those of your own. Tell your parents what you care about, and why. Understanding your values might help them see your purposes in life. A good relationship with your parents can make you a better and happier person. It is worth having a try. (1)From the passage we know_______ have a communication problem. A. parents and children of all ages B. children and other people C. parents and their school children D. teachers and their students (2)How many pieces of advice does the writer give us to bridge the generation gap? A. 5 B. 4 C. 3 D. 2 (3)The underlined phrase "cool off" in the passage means_______. A. make yourself happy B. make yourself quiet and relaxed C. become angry D. go away (4)If the values of your parents are different from those of yours, you'd better_______. A. argue with them B. keep away from them

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