求临界速度
超高半径
试计算该圆曲线的几何要素及曲线主点桩的桩号?
133013.5
'=
2
71.015()
m =
141.372()m
=
133013.5
'=2(sec 1)E R α=-=T
=160-40=12042
2tan R α
16
2(sec R α24R ()
2(q m α+
66.667()
m
p
250 925027.778250()
R m =-=
4920 230
'+
60
?=
120
14.324()
=
7530
2
120 1.24729.938123.817(
'
++=
180
7530298.127(
π
'-??