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高考单选与填空专题

1、已知集合},2,0,1{},4,2,2,1{-=-=B A 则_______,=?B A

2、函数)12(log )(5+=x x f 的单调增区间是__________

3、设复数i 满足i z i 23)1(+-=+(i 是虚数单位),则z 的实部是_________

4、根据如图所示的伪代码,当输入b a ,分别为2,3时,最后输出的m 的值是________ Read a ,b If a >b Then m ←a Else m ←b

End If Print m 5、从1,2,3,4这四个数中一次随机取两个数,则其中一个数是另一个的两倍的概率是______ 6、某老师从星期一到星期五收到信件数分别是10,6,8,5,6,则该组数据的方差___2

=s 7、已知,2)4

tan(=+

π

x 则

x

x

2tan tan 的值为__________

8、在平面直角坐标系xOy 中,过坐标原点的一条直线与函数x

x f 2

)(=的图象交于P 、Q 两点,则线段PQ 长的最小值是________

9、函数??,,(),sin()(w A wx A x f +=是常数,)0,0>>w A 的部分图象如图所示,则

____)0(=f

3ππ12

7

10、已知→

→21,e e 是夹角为π3

2

的两个单位向量,,,22121→→→→→→+=-=e e k b e e a 若0=?→→b a ,则

k 的值为

11、已知实数0≠a ,函数?

??≥--<+=1,21

,2)(x a x x a x x f ,若)1()1(a f a f +=-,则a 的值为

________

12、在平面直角坐标系xOy 中,已知点P 是函数)0()(>=x e x f x

的图象上的动点,该图象在P 处的切线l 交y 轴于点M ,过点P 作l 的垂线交y 轴于点N ,设线段MN 的中点的纵

2

-

O

D1A1

C1B1A

C

D

B

坐标为t ,则t 的最大值是_____________

13、设7211a a a ≤≤≤≤ ,其中7531,,,a a a a 成公比为q 的等比数列,642,,a a a 成公差为1的等差数列,则q 的最小值是________ 14、设集合},,)2(2

|

),{(222R y x m y x m

y x A ∈≤+-≤=, },,122|),{(R y x m y x m y x B ∈+≤+≤=, 若,φ≠?B A 则实数m 的取值范围是

______________

一.填空题:

1.已知集合{124}A =,

,,{246}B =,,,则A B = . 2. 某学校高一、高二、高三年级的学生人数之比为334::,现用分层抽样的方法从该校高中三个年级的学生中抽取容量为50的样本,则应从高二年级抽取 名学生

3. 设a b ∈R ,

,117i

i 12i

a b -+=-(i 为虚数单位),则a b +的值为 .

4. 右图是一个算法流程图,则输出的k 的值是 .

5. 函数6()12log f x x =-的定义域为 .

6. 现有10个数,它们能构成一个以1为首项,3-为公比的等比数列,若从这10个数中随机抽取一个数,则它小于8的概率是 .

7.如图,在长方体1111ABCD A B C D -中,

3cm AB AD ==,12cm AA =,则四棱锥D D BB A 11-的体积为

cm 3.

8. 在平面直角坐标系xOy 中,若双曲线

22

214

x y m m -=+的离心率为5,则m 的值为 .

9. 如图,在矩形ABCD 中,22AB BC ==,,点E

为BC 的中点,点F 在边CD 上,若2AB AF = ,则AE BF

的值是 .

C

E

F

D

10. 设()f x 是定义在R 上且周期为2的函数,在区间[11]-,

上,0111()201

x x ax f x bx x <+-??

=+??+?≤≤≤,

,,,其中a b ∈R ,

.若1322f f ????

= ? ?????

,则3a b +的值为 . 11. 设α为锐角,若4cos 65απ?

?+= ??

?,则)122sin(πα+的值为 .

12. 在平面直角坐标系xOy 中,圆C 的方程为228150x y x +-+=,若直线2y kx =-上至少存在一点,使得以该点为圆心,1为半径的圆与圆C 有公共点,则k 的最大值是 .

13. 已知函数2()()f x x ax b a b =++∈R ,的值域为[0)+∞,,若关于x 的不等式()f x c <的解集为(6)m m +,

,则实数c 的值为 . 14. 已知正数a b c ,

,满足:4ln 53ln b c a a c c c a c b -+-≤≤≥,,则b

a

的取值范围是 .

一、选择题:本大题共12小题,每小题5分,共60分。在每小题给出的四个选项中,只有

一项是符合题目要求的。 1.已知全集R =U ,集合{

}

2

40M x x =-≤ ,则U M =e (A ){}

22x x -<< (B ){}

22x x -≤≤

(C ){}22x x x <->或

(D ) {}

22x x x ≤-≥或

(2) 已知

2a i

b i i +=+(,)a b R ∈,其中i 为虚数单位,则a b +=

(A )-1

(B )1

(C )2

(D )3

(3)

)13(log )(2+=x

x f 的值域为

(A )(0,)+∞ (B )[)0,+∞

(C )(1,)+∞

(D )[)1,+∞

(4)在空间,下列命题正确的是

(A )平行直线的平行投影重合 (B )平行于同一直线的两个平面 (C )垂直于同一平面的两个平面平行 (D )垂直于同一平面的两个平面平行

(5)设()f x 为定义在R 上的函数。当0x ≥时,()22()x f x x b b =++为常数,

则(1)f -=

(A ) -3 (B ) -1 (C ) 1 (D ) 3 (6)在某项体育比赛中一位同学被评委所打出的分数如下: 90 89 90 95 93 94 93 去掉一个最高分和一个最低分后,所剩数据的平均分值为和方差分别为 (A ) 92,2 (B ) 92 ,2.8 (C ) 93,2 (D )93,2.8 (7)设{}n a 是首项大于零的等比数列,则“12a a p ”是“数列{}n a 是递增数列”的 (A )充分而不必要条件 (B )必要而不充分条件 (C )充分而不必要条件 (D )既不充分也不必要条件

(8)已知某生产厂家的年利润y (单位:万元)与年产量x (单位:万件)的函数关系式

为2

1812343

y x x =-+-,则使该生产厂家获取最大年利润的年产量为

(A )13万件 (B )11万件

(C )9万件 (D )7万件

(9)已知抛物线22(0)y px p =>,过其焦点且斜率为1的直线交抛物线于,A B 两点,若

线段AB 的中点的纵坐标为2,则该抛物线的标准方程为 (A )1x = (B )1x =-

(C )2x = (D )2x =-

(10)观察2'

()2x x =,4'

2

()4x x =,(cos )'sin x x =-,由归纳推理可得:若定义在R 上的

函数()f x 满足()()f x f x -=,记()()g x f x 为的导函数,则()g x -

(A )()f x

(B )()f x - (C )()g x (D )()g x -

(11)函数2

2x

y x =-的图像大致是

(12)定义平面向量之间的一种运算“e ”如下:对任意的(,)a m n =,(,)b p q =,令

a b mq mp =-e .下面说法错误的是

(A )若a b 与共线,则0a b =e

(B )a b b a =e e

(C )对任意的,R a a λλλ∈e e 有()b=(b)

(D )2

2

22

()()a b a b a b +?=e

第Ⅱ卷(共90分)

二、填空题:本大题共4小题,每小题4分,共16分

(13)执行右图所示流程框图,若输入4x =,则输出y 的值为____________________.

(14) 已知(,)x y R +

∈,且满足

134

x y

+=,则xy 的最大值为____________________. (15)在ABC ?中,角A B C 、、所对的边分别为a 、b 、c .若

,2,2==b a 2c o s s i n =+B B ,,则角A 的大小为____________________.

(16)已知圆C 过点(1,0),且圆心在x 轴的正半轴上,直线1:-=x y l 被该圆所截得的弦

长为22,则圆C 的标准方程为____________ 四

一、选择题:本大题共10小题,每小题5分,共50分。在每小题给出的四个备选项中,只有一项是符合题目要求的。

1.直线1y x =+与圆22

1x y +=的位置关系为( )

A .相切

B .相交但直线不过圆心

C .直线过圆心

D .相离

2.已知复数z 的实部为1-,虚部为2,则

5i

z

=( ) A .2i - B .2i + C .2i -- D .2i -+

3.2

8

2()x x

+

的展开式中4x 的系数是( ) A .16

B .70

C .560

D .1120

4.已知1,6,()2==-= a b a b a ,则向量a 与向量b 的夹角是( )

A .

6

π

B .

4

π C .

3

π D .

2

π 5.不等式2

313x x a a +--≤-对任意实数x 恒成立,则实数a 的取值范围为( )

A .(,1][4,)-∞-+∞

B .(,2][5,)-∞-+∞

C .[1,2]

D .(,1][2,)-∞+∞

6.锅中煮有芝麻馅汤圆6个,花生馅汤圆5个,豆沙馅汤圆4个,这三种汤圆的外部特征完全相同。从中任意舀取4个汤圆,则每种汤圆都至少取到1个的概率为( )

A .

891 B .2591 C .4891 D .60

91

7.设ABC ?的三个内角,,A B C ,向量(3sin ,sin )A B =m ,(cos ,3cos )B A =n ,若

1cos()A B =++ m n ,则C =( )

A .

6

π B .

3

π C .

23

π D .

56

π 8.已知2

2lim(

)21

x x ax b x →∞--=+,其中,a b R ∈,则a b -的值为( ) A .-6

B .2-

C .2

D .6

9.已知二面角l αβ--的大小为0

50,P 为空间中任意一点,则过点P 且与平面α和平面

β所成的角都是025的直线的条数为( )

A .2

B .3

C .4

D .5

10.已知以4T =为周期的函数21,(1,1]

()12,(1,3]m x x f x x x ?-∈-?=?--∈??,其中0m >。若方程

3()f x x =恰有5个实数解,则m 的取值范围为( )

A .158

(

,)33

B .15

(

,7)3

C .48(,)33

D .4(,7)3

二、填空题:本大题共5小题,每小题5分,共25分.把答案写在答题卡相应位置上.

11.若{}

3A x R x =∈<,{}

21x

B x R =∈>,则A B = .

12.若1

()21

x

f x a =

+-是奇函数,则a = 13.将4名大学生分配到3个乡镇去当村官,每个乡镇至少一名,则不同的分配方案有 种(用数字作答).

14.设12a =,121n n a a +=

+,21

n n n a b a +=-,*

n N ∈,则数列{}n b 的通项公式

n b = .

15.已知双曲线22

221(0,0)x y a b a b

-=>>的左、右焦点分别为12(,0),(,0)F c F c -,若

双曲线上存在一点P 使

1221sin sin PF F a

PF F c

=,则该双曲线的离心率的取值范围是 .

一.选择题:共10个小题,每小题5分,满分50分,每小题只有一个答案是符合要求的答

案。

1.第二十九届夏季奥林匹克运动会将于2008年8月8日在北京举行,若集合{}A =参加北京奥运会比赛的运动员,集合{}B =参加北京奥运会比赛的男运动员,集合

{}C =参加北京奥运会比赛的女运动员,则下列关系正确的是

A .A ?

B B .B ?

C C ..A ∩B =C

D ..B ∪C =A 2.已知0<a <2,复数z =a +i (i 是虚数单位),则|z |的取值范围是

A .(1,3)

B . (1,5)

C .(1,3)

D .(1,5) 3.已知平面向量()1,2a = ,()2,b m =-

,且//a b ,则23a b +=

A .()2,4--

B .()3,6--

C .()4,8--

D .()5,10--

4.记等差数列{a n }的前n 项和为S n ,若S 1=4,S 4=20,则该数列的公差d =

A .7

B .6

C .3

D .2

5.已知函数2

()(1cos2)sin f x x x =+,x ∈R,则()f x 是 A .最小正周期为π的奇函数 B .最小正周期为π的偶函数

C .最小正周期为

2

π

的奇函数 D .最小正周期为

2

π

的偶函数 6.经过圆x 2+2x +y 2=0的圆心G ,且与直线

x +y =0垂直的直线方程是

A .10x y -+=

B .10x y ---

C .10x y +-=

D .10x y ++= 7.将正三棱柱截去三个角(如图1所示A ,B ,C 分别是△CHI 三边的中点)得到几何体如图2,则该几何体按图2所示方向的侧视图(或称左视图)为

D

C

B

B

E

B E

B

E

A

E

B

8.命题“若函数()log a f x x =(a >0,a ≠1)在其定义域内是减函数,则log 2a <0”的逆否命题是

A .若log 2a <0,则函数()log a f x x =(a >0,a ≠1)在其定义域内不是减函数

侧视A B

C

D E

F

I

H G

F

E

D C B A

B .若log 2a ≥0,则函数()log a f x x =(a >0,a ≠1)在其定义域内不是减函数

C .若log 2a <0,则函数()log a f x x =(a >0,a ≠1)在其定义域内是减函数

D .若log 2a ≥0,则函数()log a f x x =(a >0,a ≠1)在其定义域内是减函数 9.设a ∈R ,若函数y =e 5+ax ,x ∈R 有大于零的极值点,则 A .a <1-

B .a >1-

C .a >1c

-

D .a <1c

-

10.设a , b ∈R ,若a b ->0,则下列不等式中正确的是

A .b a ->0

B .a 3+b 3<0

C .b +a >0

D .2

2

a b -<0 二、填空题:本大题共5小题,考生作答4小题,每小题5分,满分20分. (一)必做题(11-13题)

11.为了调查某厂工人生产某种产品的能力,随机抽查了20位工人某天生产该产品的数量.产品数量的分组区间为[)45,55,[)[)[)[)55,65,65,75,75,85,85,95,由此得到频率分布直方图如图3,则这20名工人中一天生产该产品数量在[)55,75的人数是 .

产品数量

频率/组距

95

85

75

65

55

45

0.0400.0350.0300.0250.0200.0150.0100.005

图3

12.若变量x ,y 满足240,250,0,0,

x y x y x y +≤??+≤?

?≥??≥?则z =3x +2y 的最

大值是________。

图4

13.阅读图4的程序框图,若输入m =4,n =3,则输出a =_______,i =________。 (注:框图中的赋值符号“=”,也可以写成“←”或“:=”)

(二)选择题(14-15题,考生只能从中选做一题)

14.(坐标系与参数方程选做题)已知曲线C 1与C 2的极坐标方向分别为cos 3ρθ=,

4cos ρθ=(ρ≥0,0≤θ<

2

π),则曲线C 1与C 2交点的极坐标为________. 15.(几何证明选讲选做题)已知P A 是圆O 的切点,切点为A ,P A =2.AC 是圆O 的直径,PC 与圆O 交于B 点,PB =1,则圆O 的半径R =________.

是a=m ?i

i=1

i=i+1

结束输出a,i

n 整除a?

输入m,n 开 始

一、选择题:本大题共10小题,每小题5分,满分50分,在每小题给出的四个

选项中,只有一项是符合题目要求的。

1.设复数z 满足iz = 1,其中i 为虚数单位,则z = A

A .- i

B .i

C .- 1

D .1 2.已知集合

{}{}22(,),1,(,),1A x y x y x y B x y x y x y =+==+=为实数,且为实数,且,则

A B 的元素个数为C

A .4

B .3

C .2

D . 1 3.已知向量(1,2),(1,0),(3,4)a b c ===.若λ为实数,()//,a b c λλ+=则 B

A .

14 B .1

2

C .1

D . 2 4.函数1

()lg(1)1f x x x

=

++-的定义域是C A .(,1)-∞- B .(1,)+∞ C .(1,1)(1,)-+∞ D .

(,)-∞+∞

5.不等式2210x x -->的解积是D

A .1

(,1)2- B . (1,)+∞ C . (,1)(2,)-∞+∞ D .

1

(,)(1,)2

-∞-+∞

6.已知平面直角坐标系xOy 上的区域D 由不等式组0222x y x y

?≤≤?

≤??

≤?给定,若(,)

M x y 为D 上的动点,点A 的坐标为(2,1),z OM OA =

则的最大值为B

A .3

B .4

C .32

D .

42

7.正五棱柱中,不同在任何侧面且不同在任何底面的两顶点的连线称为它的对角线,那么一个正五棱柱的对角线条数共有D

A .20

B .15

C .12

D . 10 8.设圆22(3)10C x y y C +-==与圆外切,与直线相切,则圆的圆心轨迹为 A A .抛物线 B .双曲线 C .椭圆 D . 圆 9.如图,某几何体的正视图(主视图),侧视图(左视图)和俯视图分别是等边三角

形,等腰三角形和菱形,则该几何体体积为C

A .43

B .4

C .23

D . 2 10.设(),(),()f x g x h x 是R 上的任意实值函数,如下定义两个函数

()()()():f g x f g x ? 和对任意,()()(());()()()(),x R f g x f g x f g x f x g x ∈=?= 则下列等式恒成立的是B

A .(())()(()())()f g h x f h g h x ?=??

B .(())()(()())()f g h x f h g h x ?=?

C .(())()(()())()f g h x f h g h x =

D .(())()(()())()f g h x f h g h x ??=???

二、填空题:本大题共5小题,考生作答4小题,每小题5分,满分20分。 (一)必做题(11—13题)

11.已知{}n a 是递增等比数列,2432,4,a a a q =-==则此数列的公比 2 . 12.设函数3()cos 1.()11,()f x x x f a f a =+=-=若则 -9 .

13.为了解篮球爱好者小李的投篮命中率与打篮球时间之间的关系,下表记录了

小李某月1号到5号每天打篮球时间x (单位:小时)与当天投篮命中率y 之间的关系:

时间x

1 2 3 4 5 命中率y

0.4

0.5

0.6

0.6

0.4

小李这5天的平均投篮命中率为 0.5 ;用线形回归分析的方法,预测小李该月

6号打6小时篮球的投篮命中率为 0.53 .

(二)选做题(14—15题,考生只能从中选做一题) 14.(坐标系与参数方程选做题)已知两曲线参数方程分别为

俯视图

侧视图

正视图

23

2

2

5cos (0)sin x y θθπθ?=?≤≤?=??和25()4x t t R y t

?=?

∈?

?=?,它们的交点坐标为 . 15.(几何证明选讲选做题)如图,在梯形ABCD 中,//,AB CD 4,2,,3//AB CD E F AD BC EF EF AB ===分别为,上的点,且,, 则梯形ABFE 与梯形EFCD 的面积比为

5

7

F

D C

B

A E

1 【答案】{}6,4,2,1

【解析】根据集合的并集运算,两个集合的并集就是所有属于集合A和集合B的元素组成

的集合,从所给的两个集合的元素可知,它们的元素是1 ,2,4,6,所以答案为{}6,4,2,1. 【点评】本题重点考查集合的运算.容易出错的地方是审错题目,把并集运算看成交集运算.属于基本题,难度系数较小. .

2 【答案】15

【解析】根据分层抽样的方法步骤,按照一定比例抽取,样本容量为50,那么根据题意得:从高三一共可以抽取人数为:1510

3

50=?

人,答案 15 . 【点评】本题主要考查统计部分知识:抽样方法问题,分层抽样的具体实施步骤.分层抽样也叫做“按比例抽样”,也就是说,要根据每一层的个体数的多少抽取,这样才能够保证样本的科学性与普遍性,这样得到的数据才更有价值、才能够较精确地反映总体水平,本题属于容易题,也是高考热点问题,希望引起重视.

3 【答案】8 【解析】据题i i

i i i i i i bi a 355

1525)21)(21()21)(711(21711+=+=+-+-=--=+,所以 ,3,5==b a

从而 8=+b a .

【点评】本题主要考查复数的基本运算和复数相等的条件运用,属于基本题,一定要注意审题,对于复数的除法运算,要切实掌握其运算技巧和常规思路,再者,需要注意分母实数化的实质.

4 【答案】5

【解析】根据循环结构的流程图,当1=k 时,此时0452

=+-k k ;不满足条件,继续执

行循环体,当2=k 时,6452

-=+-k k ;不满足条件,继续执行循环,当3=k 时,

2452-=+-k k 不满足条件,然后依次出现同样的结果,当5=k 时,此时4452=+-k k ,此时满足条件跳出循环,输出k 的值为5.

【点评】本题主要考查算法的定义、流程图及其构成,考查循环结构的流程图.注意循环条件的设置,以及循环体的构成,特别是注意最后一次循环的k 的值.这是新课标的新增内容,

也是近几年的常考题目,要准确理解循环结构流程图的执行过程. 5 【答案】(

0,6??

【解析】根据题意得到 0log 216≥-x ,同时,x >0 ,解得2

1

log 6≤x ,解得6≤x ,又x >0,所以函数的定义域为:(

0,6?? .

【点评】本题主要考查函数基本性质、对数函数的单调性和图象的运用.本题容易忽略x >0这个条件,因此,要切实对基本初等函数的图象与性质有清晰的认识,在复习中应引起高度重视.本题属于基本题,难度适中. 6 答案】

5

3 【解析】组成满足条件的数列为:.19683,6561,2187,729,243,81

,27.9,3,1-----从中随机取出一个数共有取法10种,其中小于8的取法共有6种,因此取出的这个数小于8的概率为

5

3

. 【点评】本题主要考查古典概型.在利用古典概型解决问题时,关键弄清基本事件数和基本事件总数,本题要注意审题,“一次随机取两个数”,意味着这两个数不能重复,这一点要特别注意.

7 【答案】3

6cm

【解析】如图所示,连结AC 交BD 于点O ,因为 平面D D BB ABCD 11⊥,又因为

BD AC ⊥,所以,D D BB AC 11平面⊥,所以四棱锥D D BB A 11-的高为AO ,根据题

意3cm AB AD ==,所以2

2

3=

AO ,又因为32cm BD =,12cm AA =,故矩形D D BB 11的面积为262cm ,

从而四棱锥D D BB A 11-的体积3132

626cm 32

V =??=. 【点评】本题重点考查空间几何体的体积公式的运用.本题综合性较强,结合空间中点线面的位置关系、平面与平面垂直的性质定理考查.重点找到四棱锥D D BB A 11-的高为AO ,这是解决该类问题的关键.在复习中,要对空间几何体的表面积和体积公式记准、记牢,并且会灵活运用.本题属于中档题,难度适中. 8 【答案】2

A B

【解析】根据题目条件双曲线的焦点位置在x 轴上(否则不成立),因此m >0,由离心率

公式得到

54

2=++m

m m ,解得 2=m . 【点评】本题考查双曲线的概念、标准方程和简单的几何性质.这是大纲中明确要求的,在对本部分复习时要注意:侧重于基本关系和基本理论性质的考查,从近几年的高考命题趋势看,几乎年年都有所涉及,要引起足够的重视.本题属于中档题,难度适中. 9 【答案】2

【解析】根据题意,→

+=DF BC AF 所以

()cos022,

AB AF AB BC DF AB BC AB DF AB DF AB DF DF →→→→→→→→→→→→→→

?=?+=?+?=?=??==从而得到1=→

DF ,又因为→

+=+=CF BC BF DF AD AE ,,所以

2180cos 00)()(2

=?+++=+?+=??→

→→→→→→→→CF DF BC CF BC DF AD BF AE .

【点评】本题主要考查平面向量的基本运算,同时,结合平面向量的数量积运算解决.设法找到1=→

DF ,这是本题的解题关键,本题属于中等偏难题目. 10 【答案】10- .

【解析】因为1322f f ????

= ? ?????

,函数()f x 的周期为2,所以

)21()223()21(-=-=f f f ,根据0111()201

x x ax f x bx x <+-??

=+??

+?≤≤≤,

,,,得到223-=+b a ,

又)1()1(-=f f ,得到02,2

2

1=++=+-b a b a 即,结合上面的式子解得4,2-==b a ,所以103-=+b a .

【点评】本题重点考查函数的性质、分段函数的理解和函数周期性的应用.利用函数的周期性将式子化简为)2

1

()223()21(-=-=f f f 然后借助于分段函数的解析式解决.属于中档题,难度适中.

A

B

C

E

F

D

11 【答案】

50

2

17 【解析】根据4cos 65απ??+= ???

,2571251621)6(cos 2)32cos(2

=-?=-+=+παπα,

因为0)3

2c o s ( π

α

+,所以

25242571)32sin(2

=??

?

??-=+π

α,因为

50

2

174sin )32cos(4cos )32sin(]4)32sin[()12

2sin(=

+-+=-+

=+

ππαππαππ

απ

α. 【点评】本题重点考查两角和与差的三角公式、角的灵活拆分、二倍角公式的运用.在求解三角函数值时,要注意角的取值情况,切勿出现增根情况.本题属于中档题,运算量较大,难度稍高.

12 【答案】

3

4

【解析】根据题意228150x y x +-+=将此化成标准形式为:()1422

=+-y x ,得到,该圆的圆心为M ()0,4半径为1 ,若直线2y kx =-上至少存在一点,使得以该点为圆心,1为半径的圆与圆C 有公共点,只需要圆心M ()0,4到直线2y kx =-的距离11+≤d ,即可,所以有

21

242≤+-=

k k d ,化简得0)43(≤-k k 解得3

4

0≤

≤k ,所以k 的最大值是34 .

【点评】本题主要考查直线与圆的位置关系、点到直线的距离公式、圆的一般式方程和标准方程的互化,考查知识较综合,考查转化思想在求解参数范围中的运用.本题的解题关键就是对若直线2y kx =-上至少存在一点,使得以该点为圆心,1为半径的圆与圆C 有公共点,这句话的理解,只需要圆心M ()0,4到直线2y kx =-的距离11+≤d 即可,从而将问题得以转化.本题属于中档题,难度适中. 13 【答案】9

【解析】根据函数0)(2

≥++=b ax x x f ,得到042

=-b a ,又因为关于x 的不等式

()f x c <,可化为:20x ax b c ++-<,它的解集为()6,+m m ,设函数

c b ax x x f -++=2)(图象与x 轴的交点的横坐标分别为21,x x ,则

6612=-+=-m m x x ,从而,36)(212=-x x ,即364)(21221=-+x x x x ,又因为 a x x c b x x -=+-=2121,,代入得到 9=c .

【点评】本题重点考查二次函数、一元二次不等式和一元二次方程的关系,根与系数的关系.二次函数的图象与二次不等式的解集的对应关系要理清.属于中档题,难度不大. 14 【答案】[]7,e

【解析】根据条件4ln 53ln b c a a c c c a c b -+-≤≤≥,

,()c

b

c c b c a ln ln ln =-≤,得到 ln ,1a

c b a b

e c c c

≥≥>,得到c b <.又因为b a c ≤-35,所以35a b c +<,由已知a c b -≤4,

得到4a b c +>

.从而

b b

a ≤+4

,解得31≥a b . 【点评】本题主要考查不等式的基本性质、对数的基本运算.关键是注意不等式的等价变形,做到每一步都要等价.本题属于中高档题,难度较大.

、选择题:本题考查基础知识和基本运算,每小题5分,满分60分。 (1) C (2) B (3) A (4) D (5) A (6) B (7)C (8)C (9)B (10)D (11)A (12)B

二、填空题:本题考 查基础知识和基本运算,每小题4分,满分16分。 (13)54- (14)3 (15)6

π (16)22

(3)x y -+=4

四 参考答案

一、选择题:每小题5分,满分50分

(1) B (2) A (3) D (4) C (5) A (6) C (7) C (8) D (9) B (10) B 二.填空题:每小题5分,满分25分 (11) (0,3) (12) 12

(13) 36 (14) 1

2n + (15) (1, 21+)

2008年全国高考数学试题(文科)

广东卷参考答案

一.选择题 DBCCD AABAC

二.填空题 11.13; 12.70; 13.12,3; 14.23,

,23,66ππ???

?

- ? ??

???

; 15.3

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