文档库 最新最全的文档下载
当前位置:文档库 › 模块综合测评(三)

模块综合测评(三)

模块综合测评(三)
模块综合测评(三)

模块综合测评(三)

Ⅰ.阅读理解(共15小题;每小题2分,满分30分)

阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项。

A

Are you interested in country music? I like it very much! It will take me away for a while after I am tired. The guitars and songs will take me to mountains and fields.

Country music usually talks of everyday life and feelings. It's the spirit of America, easy to understand, slow and simple.

Country music developed in the Southern United States. It was the folk music of American countryside. Many of songs tell about the lives of farmers. They talk about love, crops or death.

The life of the countryside can be hard, so the words in country music are often sad. At first, people played the music only at family parties. But it became more popular later. In the 1920s, people played country songs on the radio, and they made them into records.

When people in the countryside moved to towns and cities to look for work, they took their music with them. Country music continued to change and became popular across America.

John Denver was one of America's most famous country singers in the 1970s.His song Take Me Home, Country Roads is well-known and people still play it today.

1.Country music is usually about .

A.everyday life and feelings

B.farmers' feelings

C.the lives of workers

D.the lives of farmers

【解析】细节理解题。由文章第二段第一句可知乡村音乐是关于日常生活和感情的。

【答案】 A

2.People began to make country song records

A.in the 1920s B.in 1920

C.in the 1970s D.in 1970

【解析】细节理解题。由文章第四段第四句可知A项正确。

【答案】 A

3.Why did country music bee popular in America?

A.Because city people liked the music.

B.Because farmers moved to cities with their music and it continued to change.

C.Because country music talked about city people's lives.

D.Because country music developed in the Southern Africa.

【解析】细节理解题。由文章倒数第二段可知农民们带着音乐进城使得乡村音乐流行起来。

【答案】 B

4.Who is famous for the song Take Me Home, Country Roads?

A.A farmer in the countryside.

B.A person who moved to towns.

C.John Denver.

D.John Denver's brother.

【解析】细节理解题。由文章最后一段可知这首歌是约翰·丹佛的。

【答案】 C

B

Mozart was one of the greatest posers who ever lived. He was born in Salzburg, Austria, in 1756. Even when he was very young, Mozart loved music. His father, who was the leader of an orchestra, was very happy that his son was so interested in music. When Mozart was three years old, he learned to play the harpsichord, which is a kind of piano. Mozart began to pose music at the age of five, and his father took him to play in front of the kings and queens of Europe.

At one concert, one of the violinists was missing from the orchestra. Mozart picked up a violin and played the music without a mistake. Mozart's father and the other players in the orchestra were surprised. Mozart had never been taught to play the violin! Mozart continued traveling around Europe with his father, who was his teacher in everything. He posed many pieces for the piano, the violin, and later for full

orchestra.

Mozart could write down a piece of music even if he had heard it only once. One day, he went to hear a group of people singing in a big church in Rome. The song was very special. The church leader said that people could sing the song only once a year, and only in his church. No one else was allowed to have the music. Mozart listened to the song. Although it was very difficult and long, Mozart went back home and wrote down the whole piece from memory. The head of the church heard about this, and instead of being angry with Mozart, he gave him a prize.When Mozart grew up, people were not so interested in him. He worked as a teacher and pianist, but he did not make much money. In 1791, at the age of 35, he died. He was so poor that there was not enough money for him to have a proper grave. No one knows where he is buried.

5. The story is mainly about .

A.Mozart and his music

B.a leader of an orchestra

C.the life of a great poser

D.the head of a church in Rome

【解析】从全文可知本文主要讲述了一位伟大音乐家的一生。

【答案】 C

6. Mozart's father helped Mozart a lot by .

A.teaching him about music

B.giving him a violin to play with

C.sending him to a music school

D.giving him a lot of money

【解析】从第一段和第二段可知答案。

【答案】 A

7.When Mozart was only three years old, he .

A.went to Rome

B.began to sing

C.began to pose music

D.played the harpsichord

【解析】从第一段的第五句可知答案。

【答案】 D

8. Although Mozart was one of the world's greatest posers, .

A.he died poorly

B.he did not teach anyone

C.he did not know many famous people

D.he couldn't play the piano or violin

【解析】从最后一段可知答案。

【答案】 A

C

You wake up in the morning, the day is beautiful and the plans for the day are what you have been looking forward to for a long time. Then the telephone rings, you say hello, and the drama starts. The person on the other end has a depressing(令人沮丧的) tone in his voice as he starts to tell you how terrible his morning is and that there is nothing to look forward to. You are still in a wonderful mood? Impossible!

municating with negative(消极的) people can wash out your happiness. It may not change what you think, but municating long enough with them will make you feel depressed for a moment or a long time.

Life brings ups and downs, but some people are stuck in the wrong idea that life has no happiness to offer. They only feel glad when they make others feel bad. No wonder they can hardly win others' pity or respect.

When you municate with positive(积极的) people, your spirit stays happy and therefore more positive things are attracted. When the dagger(匕首) of a negative person is put in you, you feel the heavy feeling that, all in all, brings you down.

Sometimes we have no choice but to municate with negative people. This could be a co-worker, or relative. In this case, say what needs to be said as little as possible. Sometimes it feels good to let out your anger back to a negative person, but all this is to lower you to that same negative level and they won't feel ashamed of themselves about that.

Negativity often affects happiness without even being realized. The negative words of another at the start of the day can cling to(附着) you throughout the rest of your day, which makes you feel bad and steals your happiness. Life is too short to feel

negative. Stay positive and avoid negativity as much as possible.

【语篇解读】本文介绍了同消极的人和积极的人交往的不同之处。

9.How can negative people have effect on us?

A.By telling us the nature of life.

B.By influencing our emotion.

C.By paring their attitude to life with ours.

D.By changing our way of thinking.

【解析】细节理解题。根据文中第一、二段可得知,与消极的人交谈会使自己感到郁闷,所以消极的人是会影响到我们的情绪和情感的。

【答案】 B

10.Some negative people base their happiness on .

A.other people's pity for them

B.building up a positive attitude

C.making other people unhappy

D.other people's respect for them

【解析】细节理解题。从第三段“They only feel glad when they make others feel bad.”可推断出消极的人是把自己的快乐建立在别人的痛苦之上。

【答案】 C

11.According to the passage, to reduce negative people's influence on us, we are advised .

A.to change negative people's attitude to life

B.to show our dissatisfaction to negative people

C.to municate with negative people as little as possible

D.to make negative people feel ashamed of themselves

【解析】细节理解题。根据倒数第二段的“In this case,say what needs to be said as little as possible.”得出答案选C。

【答案】 C

D

The arts,especially music,should be part of every school's lessons at every grade level.Students would be much smarter if they had some musical experience.They

could improve their classroom skills,like paying attention and following directions.People develop all these skills when they learn music.Making music also lets children use their imagination.It provides students with a chance to try out their own ideas.

Music not only makes children better students,but also gives them something positive to do.In a music program,children can be part of a band instead of joining a gang (团伙).Parents can enjoy listening to their children's music instead of seeing them glued to a puter or TV screen.In a school band,students get to be part of a team.They can get along well with old friends and make new friends through music.

Music builds self-confidence,too.It gives children a sense of achievement and success.Making music is something for them to be proud of,and it lets kids practice performing in front of an audience.Music gives children an opportunity for self-expression,and that helps develop their self-confidence.

Once again,music is important because it can make children better students,give them something positive to do,and build their character.That is why music should be offered in every single grade in every school.

12.According to the passage,music could make students smarter by .A.improving their classroom skills and paying attention

B.improving their classroom skills and imagination

C.improving their attention,direction and imagination

D.learning music,making music and trying out their own ideas

【解析】细节理解题。根据第一段“Students would be much smarter if they had some musical experience.”和“They could improve their classroom skills,...”以及“Making music also lets children use their imagination”可知音乐可以培养孩子们的课堂技能,使他们发挥想象力,从而变的更为聪明,选B。

【答案】 B

13.What does the underlined phrase “glued to”in the second paragraph mean?

A.Unwilling to turn on.

B.Always looking.

C.Unwilling to leave.

D.Always playing.

【解析】猜测词义题。从情理可知孩子们喜欢看电视,玩电脑,而且不愿意离开,由下而上此判断该词义为“unwilling to leave”,选C。

【答案】 C

14.The third paragraph mainly tells us that music could .

A.give children self-expression and self-confidence

B.bring to children achievement and success

C.give children something to be proud of

D.develop children's self-confidence

【解析】主旨大意题。第三段首句提出Music builds self-confidence,too.“音乐也构建自信”,然后对此进行解释分析,由此判断此句为主题句,故答案选D。

【答案】 D

15.What's the best title of this passage?

A.Music is a must as a course at school

B.Music builds children's self-confidence

C.Music makes students much smarter

D.Learning music and making music

【解析】主旨大意题。文章开门见山提出“The arts,especially music,should be part of every school's lessons at every grade level.”这一文章的主题。然后在下文进行分析论证,由此判断A选项内容具有较高的概括性,而且针对性强,选A。

【答案】 A

Ⅱ.阅读填句(共5小题;每小题2分,满分10分)

根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。选项中有两项为多余选项。

Forgiveness

To forgive is a virtue, but no one has ever said it is easy. When someone has deeply hurt you, it can be extremely difficult to let go of your hate. However, forgiveness is possible, and it can be surprisingly beneficial to your physical and mental health. People who forgive show less sadness, anger and stress and more

hopefulness, according to a recent research.

16 Try the following steps:

Calm yourself. 17 You can take a couple of breaths and think of something that gives you pleasure: a beautiful scene in nature, or someone you love.

Don't wait for an apology. Many times the person who hurt you does not intend to apologize. They may have wanted to hurt you or they just don't see things the same way. 18 Keep in mind that forgiveness does not necessarily mean being friends again with the person who upset you.

Take the control away from your offender (冒犯者). Rethinking about your hurt gives power to the person who caused you pain. Instead of focusing on your wounded feelings, learn to look for the love, beauty and kindness around you. 19 If you understand your offender, you may realize that he or she was acting out of unawareness, fear, and even love. You may want to write a letter to yourself from your offender's point of view.

Don't forget to forgive yourself. 20 But it can rob you of your self-confidence if you don't do it.

A.Why should you forgive?

B.How should you start to forgive?

C.Recognize the benefits of forgiveness.

D.Try to see things from your offender's angle.

E.For some people, forgiving themselves is the biggest challenge.

F.To make your anger die away, try a simple stress-management technique.

G.If you wait for people to apologize, you could be waiting an awfully long time.

【答案】16-20BFGDE

Ⅲ.完形填空(共20小题;每小题1.5分,满分30分)

阅读下面短文,从短文后各题所给的四个选项(A、B、C和D)中,选出可以填入空白处的最佳选项。

Marianne, a schoolgirl, was learning to play the piano, and day after day her father stood behind her as she practised. How 21 and kind her father was, and how clearly he showed Marianne how to play some particularly difficult 22 . She was making progress and that was excellent.

And there, almost 23 in the big chair, sat Wolfgang, her four-year-old brother, who never had to be told to keep 24 when Marianne was practising.

One evening at sundown the father patted Marianne's shoulder saying she had done quite well. At the 25 Wolfgang climbed on his father's knee and 26 to be allowed to play the pretty piece Marianne had now 27 . What a 28 that was! Picking up his baby, the father laughed, tapped the tiny nose and 29 ,“Look at your small 30 .You cannot 31 all the notes yet. You must 32 ,little man.”

There was no end of 33 during the tea, and Marianne had to tell her mother about Wolfgang 34 to play one of the classics(经典音乐). After dinner Marianne helped 35 the dishes when the father lit his pipe.

But the pipe 36 . He was on his 37 .“Listen!”he said in an astonished voice. “Listen! Marianne is playing that piece much prettier than ever,”he 38 .

But Marianne was washing plates in the kitchen.

His wife following, he moved slowly upstairs. A lamp in one hand and his pipe in the other, he 39 open the door, and there was little Wolfgang playing in 40 . “I love it,”whispered the child.

【语篇解读】本文叙述的是父亲教女儿玛丽安妮学弹钢琴,女儿取得了很大进步。但有一天晚上,琴房传出悦耳的经典音乐,原来是玛丽安妮4岁的小弟弟正在演奏,他真是个天才。

21. A.worried B.happy

C.patient D.anxious

【解析】每当玛丽安妮练钢琴时,父亲总是站在她身后,耐心地看着她。

【答案】 C

22. A.one B.piece

C.song D.piano

【解析】父亲教玛丽安妮演奏相当难的一首曲子。some后接单数名词,表示“某一个”。

【答案】 B

23. A.disappeared B.hurt

C.lost D.missed

【解析】lost in...意为“陷入/沉浸在……之中”。这里暗示弟弟年龄小,坐在大的椅子上看不到了。

【答案】 C

24. A.watching B.calm

C.quiet D.hacking

【解析】姐姐在演奏时,弟弟从不需要别人告诉他要保持安静。

【答案】 C

25. A.moment B.time

C.point D.minute

【解析】at the moment相当于at that moment,指玛丽安妮被父亲拍肩赞扬的时刻。

【答案】 A

26. A.begged B.persuaded

C.advised D.required

【解析】beg语气强烈,意为“请求,乞求”;require含有命令之意。此处指弟弟请求父亲让他也试一试。

【答案】 A

27. A.learned B.stopped

C.mastered D.passed

【解析】master指“熟练掌握”;learn指“学习”。

【答案】 C

28. A.joke B.surprise

C.pleasure D.pity

【解析】父亲不相信4岁的儿子能演奏经典乐章,认为他是在开玩笑。

【答案】 A

29. A.suggested B.thought

C.said D.should

【解析】下文是说话的内容,故C项正确。

【答案】 C

30. A.head B.nose

C.age D.hands

【解析】弹钢琴要用手,父亲认为儿子太小,手不够大。

【答案】 D

31. A.cover B.play

C.reach D.write

【解析】cover有“覆盖”之意,这里指父亲认为儿子的手太小,不能覆盖琴键。

【答案】 A

32. A.learn B.wait

C.apologize D.try

【解析】父亲建议儿子长大一点儿后再弹钢琴。

【答案】 B

33. A.quarrel B.fun

C.laughing D.conversation

【解析】吃晚点时,玛丽安妮一家有很多乐事。no end of fun意为“没完没了的乐事”。

【答案】 B

34. A.insisting B.dreaming

C.demanding D.wanting

【解析】want to do sth.指“心里想要做某事”;demand to do sth.强调在正当理由下要求做某事。

【答案】 D

35. A.make up B.put up

C.clear away D.wash away

【解析】clear away意为“清理”,即玛丽安妮帮忙收拾餐具。

【答案】 C

36. A.put out B.went out

C.dropped down D.broke down

【解析】go out意为“熄灭”。从下文可知,父亲的烟斗点燃后又熄灭了。

【答案】 B

37.A.feet B.ear

C.eye D.watch

【解析】be on one's feet意为“站起来”。父亲这时站了起来,他以为是女儿在弹奏。

【答案】 A

38. A.answered B.whispered

C.added D.asked

【解析】父亲接着又说道。add在这里意为“补充说”。

【答案】 C

39. A.broke B.struck

C.kicked D.pushed

【解析】父亲把门推开,结果令他深感意外。push open the door把门推开。

【答案】 D

40. A.the darkness B.the light

C.the shade D.silence

【解析】in the darkness在黑暗处;in the shade在阴凉处。父亲上楼时手里拿着灯,故A项合适。这里指玛丽安妮的小弟弟正坐在黑暗的房间里演奏。

【答案】 A

Ⅳ.语法填空(共10小题;每小题1.5分,满分15分)

【导学:06590057】阅读下面材料,在空白处填入适当的内容(1个单词)或括内单词的正确形式。

Friendship is one of 41.(important) things in everyone's life. 42. is very difficult to find a better definition(定义) of friendship. A true friend is the person 43. can share all our sadness and double all our 44. (happy). In time of trial(尝试), he or she is always at our side to give us his or her help and fort.

45.(know)how valuable friendship is, we should be very careful with our 46.(choose) of a friend. We should choose those people with a good character(品质) as our friends, but we must try to avoid 47.(make) friends

with a bad man. Besides, we should forgive their mistakes and try to help them as much as possible.

A true friend can always 48. (trust), loved and respected. If you tell a friend your secrets, he or she won't tell others. Friends share their 49. (joy) and sorrows. They help each other when they are 50. trouble, and cheer each other up when they are sad. The most important thing is that a friend always understands you. In conclusion, when you have made a good friend, don't forget him or her.

【答案】 41. the most important 42.It 43.who/that 44.happiness 45. Knowing 46.choice 47.making 48.be trusted 49.joys 50.in

Ⅴ.短文改错(共10小题;每小题1分,满分10分)

假定英语课上老师要求同桌之间交换修改作文,请你修改你同桌写的以下作文。文中共有10处语言错误,每句中最多有两处。每处错误仅涉及一个单词的增加、删除或修改。

增加:在缺词处加一个漏字符(∧),并在其下面写出该加的词。

删除:把多余的词用斜线(\)划掉。

修改:在错的词下划一横线,并在该词下面写出修改后的词。

注意:1.每处错误及其修改均仅限一词;

2.只允许修改10处,多者(从第11处起)不计分。

During the weekend I travelled by the air for the first time in my life. I usual travel by train or bus. It's all cheaper and safer. But to fly in the sky was something new to me. At the end I felt a little nervous. But very soon I became exciting when I found me high up in the sky among the clouds. I also found that mountains, fields, river and so on was interestingly small. I enjoy the frightening and fortable journey very much. After all, it is more interesting take a plane than to take a car.

【答案】

During the weekend I travelled by air for the first time in my life. I usual usually travel by train or bus. It's all both cheaper and safer. But to fly in the sky was

something new to me. At the end beginning/start I felt a little nervous. But very soon I

became exciting excited when I found me myself high up in the sky among the clouds. I also

found that mountains, fields, river

rivers and so on

was

were interestingly small. I

enjoy

enjoyed

the frightening and fortable journey very much. After all, it is more interesting

take a plane than to take a car.

Ⅵ.书面表达(满分25分) 【导学:06590058】

请根据以下内容,以“Chopin—a great musician”为题,写一篇100词左右的英语短文,介绍著名的音乐家肖邦。

内容包括:

1.肖邦是世界闻名的作曲家和钢琴家。他一生创作了近200首深受人们喜爱的乐曲。1810年,肖邦出生于波兰。

2.肖邦最初接触音乐是跟随母亲学钢琴。到六岁时,肖邦创作出了一系列作品,充分展现了他非凡的音乐天赋。

3.16岁时,肖邦进入华沙音乐学院学习,师从德国音乐家约瑟夫·艾尔斯内(Józef Elsner) 。

4.离开华沙音乐学院后,肖邦到了当时的音乐圣地——维也纳。在那里,他不仅举办了多场音乐会,还发表了不少音乐作品。

5.1849年,肖邦逝世于巴黎的寓所中,结束了短短39年的生命。

参考词汇:作品position华沙音乐学院the Warsaw Conservatory of Music 寓所dwelling

【参考范文】

Chopin-a great musician

Chopin, a world-famous poser and pianist in modern times,created nearly 200 musical positions and they are still popular among people nowadays. He was born in Poland in 1810.His early training began at home, including receiving piano lessons from his mother. By the age of six, Chopin had created a series of musical positions, showing outstanding musical talent. When Chopin was sixteen, he attended the Warsaw Conservatory of Music, directed by German poser Józef Elsner. After that, Chopin went to Vienna, the unquestioned centre of music at that time, where he gave piano concerts and had lots of his works published.

In 1849,Chopin died at the age of 39 in the dwelling of Paris.

高中物理 模块综合测评(A)新人教版

模块综合测评(A) (时间60分钟,满分100分) 一、选择题(本题包括8小题,每小题6分,共48分,每小题有多项符合题目要求,全都选对的得6分,选对但不全的得3分,有选错的得0分) 1.(2016·长沙高二检测)在一定温度下,当一定量气体的体积增大时,气体的压强减小.关于其原因下列说法正确的是( ) A .单位体积内的分子数变少,单位时间内对单位面积器壁碰撞的次数减少 B .气体分子的密集程度变小,分子的平均动能不变,单位面积器壁上受到的分子平均作用力减小 C .每个分子对器壁的平均撞击力变小 D .气体分子的密集程度变小,分子势能变小 E .气体分子的密集程度变小,分子势能增大 【解析】 气体温度不变,分子的平均动能不变,气体分子对器壁的平均撞击力不变,当气体的体积增大时,气体分子的密集程度减小,气体压强减小,A 、B 正确,C 错误;气体的体积增大,分子势能增大,D 错误、E 正确. 【答案】 ABE 2.(2015·福建高考改编)如图1所示,一定质量的理想气体,由状态a 经过ab 过程到达状态b 或者经过ac 过程到达状态c .设气体在状态b 和状态c 的温度分别为T b 和T c ,在过程ab 和ac 中吸收的热量分别为Q ab 和Q ac 则下列选项不正确的是( ) 图1 A .T b >T c ,Q ab >Q ac B .T b >T c ,Q ab <Q ac C .T b =T c ,Q ab >Q ac D .T b =T c ,Q ab <Q ac E .气体在b 、c 状态内能相等 【解析】 由理想气体状态方程可知p a V a T a =p c V c T c =p b V b T b ,即2p 0·V 0T c =p 0·2V 0T b ,得T c =T b ,则气体在b 、c 状态内能相等,E 正确;因a 到b 和a 到c 的ΔU 相同,而a 到c 过程中气体体积不变,W =0,a 到b 过程中气体膨胀对外做功,W <0,根据热力学第一定律:ΔU =Q +W 可知a 到b 的吸热Q ab 大于a 到c 的吸热Q ac ,即Q ab >Q ac .选项C 正确. 【答案】 ABD 3.如图2所示,绝热的汽缸与绝热的活塞A 、B 密封一定质量的理想气体后水平放置在

2020鲁科版物理必修三 模块综合测评

模块综合测评 (时间:90分钟 分值:100分) 一、选择题(本题共10小题,每小题4分,共40分.在每小题给出的四个选项中,第1~6题只有一项符合题目要求,第7~10题有多项符合题目要求,全部选对的得4分,选对但不全的得2分,有选错的得0分) 1.下列关于静电场和磁场的说法正确的是( ) A .电场中场强越大的地方,电势一定越高 B .电场中某点的场强与试探电荷的电荷量成反比 C .磁场中某点的磁感应强度大小与小磁针受到的磁场力大小有关 D .静电荷产生的电场中电场线不闭合,通电直导线产生的磁场中磁感线是闭合的 D [电场中场强越大的地方,电势不一定越高,如负点电荷周围,越靠近点电荷,场强越大,但电势却越低,选项A 错误;电场中某点的场强是由电场本身决定的,与试探电荷存在与否无关,选项B 错误;磁场中某点的磁感应强度由磁场本身决定,与小磁针存在与否无关,选项C 错误;静电荷产生的电场中电场线是从正电荷(或无穷远处)出发终止于无穷远处(或负电荷),是不闭合的,通电直导线产生的磁场中磁感线是闭合的,选项D 正确.] 2.下列说法中正确的是( ) A .E =U d 适用于任何电场 B .E =F q 仅适用于匀强电场 C .E =k Q r 2适用于真空中的点电荷形成的电场 D . E 是矢量,由U =Ed 可知,U 也是矢量 C [E =U d 只适用于匀强电场,A 错;E =F q 适用于任何电场,B 错;E =k Q r 2适用于真空中的点电荷形成的电场,C 对;在公式U =Ed 中,E 是矢量,U 是标量, D 错.] 3.关于电场强度和磁感应强度,下列说法正确的是( )

2016-2017学年高中英语模块综合测评1Modules1~2外研版选修6

模块综合测评(一) Modules 1~2 Ⅰ.阅读理解(共15小题;每小题2分,满分30分) A When you go to St.Petersburg,the number of attractions can seem overwhelming.If you' re short on time,or just want to make sure to hit the highlights,these are the top m ust-see sights in St.Petersburg. The Hermitage Museum The Hermitage Museum is one of the most important sights to see for any visitor to St.Petersburg.There you can see lots of different paintings of old masters inside the Hermitage.Prepare to come face-to-face with classic Western artists. The Russian Museum The Russian Museum holds one of the largest collections of Russian art in the world.View Russian art creations through the ages, from Byzantine-style icons to the Socialist Realism of Stalin's times. Kizhi Island Kizhi Island is an open-air museum of wooden buildings from the Karelia Region of Russia.These impressive structures are made without any nails (钉子)—the wood fits together with joints and grooves(沟槽). Peterhof Peterhof is as beautiful as it is fun.You'll be charged for admission(门票),but go to Peterhof when the fountains(喷泉) are working during the day in the summer.They are shut off in winter as well as in the evenings. The Church of Our Savior on Spilled Blood Love it or hate it, the Church of Our Savior on Spilled Blood is an attractive must-see sight.The beautiful look may make your eyes brighten, and the paintings inside the church will make you say “Wow!” The Bronze Horseman Statue The Bronze Horseman statue is a part of Russian Culture and a symbol of St.Petersburg.Made famous by Alexander Pushkin(普希金), this statue of Peter the Great sitting on his horse can truly show Peter the Great's influence on the Russian idea of greatness. 1.If you're interested in paintings,you'd better go to .

高一数学必修1教师用书:模块综合检测(苏教版)

模块综合检测 (时间:120分钟 满分:160分) 一、填空题(本大题共14个小题,每小题5分,共70分.把答案填在题中的横线上) 1.若幂函数y =f (x )的图象经过点(9,13 ),则f (25)的值是________. 解析:设f (x )=x α,将(9,13)代入得9α=13 , 即32α=3-1,∴2α=-1,∴α=-12 , ∴f (x )=x -12.∴f (25)=25-12=15 . 答案:15 2.(2011·新课标高考改编)下列函数中,既是偶函数又在(0,+∞)单调递增的函数是________. ①y =x 3 ②y =|x |+1 ③y =-x 2+1 ④y =2-|x | 解析:y =x 3为奇函数,y =-x 2+1在(0,+∞)上为减函数,y =2-|x |在(0,+∞)上为减函数.故只有②符合条件 答案:② 3.若集合A ={x |log 12 x ≤12},则?R A =________. 解析:由log 12 x ≤12得x ≥(12)12=22. ∴A =[22,+∞).∴?R A =(-∞,22 ). 答案:(-∞, 22) 4.试比较1.70.2、log 2.1 0.9与0.82.1的大小关系,并按照从小到大的顺序排列为________. 解析:log 2.10.9<0,1.70.2>0,0.82.1>0. ∵1.70.2>1.70=1,0.82.1<0.80=1, ∴log 2.10.9<0.82.1<1.70.2 .

答案:log 2.10.9<0.82.1<1.70.2 5.设集合M ={x |x -m ≤0},N ={y |y ≥-1},若M ∩N =?,则实数m 的取值范围是________. 解析:M =(-∞,m ],N =[-1,+∞),∵M ∩N =?, ∴m <-1. 答案:m <-1 6.(2012·山东高考改编)函数f (x )=1ln (x +1) + 4-x 2的定义域为________. 解析:x 满足???x +1>0,x +1≠1,4-x 2 ≥0,即???x >-1, x ≠0,-2≤x ≤2.解得-10,∴x <23 . 令u =-3x +2,∵f (u )=log 13 u 是减函数,要求f (x )的单调增区间,只需求u =-3x +2的递减区间,即(-∞,23 ). 答案:(-∞,23 ) 9.设函数f (x )=x (e x +a e -x )(x ∈R)是偶函数,则实数a 的值为________. 解析:因为f (x )是偶函数,所以恒有f (-x )=f (x ),即-x (e -x +a e x )=x (e x +a e -x ),化简得x (e -x +e x )(a +1)=0.因为上式对任意实数x 都成立,所以a =-1. 答案:-1 10.已知函数y =f (x )是R 上的奇函数,且x >0时,f (x )=2x ,函数y =f (x )的解析式为________. 解析:∵y =f (x )是R 上的奇函数,∴f (0)=0.

2018版 模块综合测评1

模块综合测评(一) (时间:100分钟;满分:120分) 【XZB2017TBYLYYB01013】Ⅰ.阅读理解(共15小题;每小题2分,满分30分) 阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项。 A On the first day of my new high school,I almost had a nervous breakdown. Everything about the school seemed so difficult.When I got home,my parents said,“You're nervous and that's okay.Everyone is af raid of high school.” I denied it.I wanted to be strong,so I refused to let anyone know about my fear,even my closest friends. On the first day I was late for every class and was constantly lost.The school seemed like a puzzle that I couldn't figure out.Was this how the whole year was going to be?I didn't think I could rise to this challenge,especially carrying a huge backpack that I could hardly lift.It was so big that I could knock someone out with it! The schoolmates seemed to regard me as a fool,and they were probably right. Despite my fears,after the first week I finally had my schedule figured out.With the exception of falling up and down the stairs a couple of times and getting laughed at,high school was turning out to be not so bad.It was actually much better than middle school and much more challenging. Since then,I've been elected vice president of my class,which wasn't much of a victory since only three people ran for the four positions. It is normal to be scared about a new school.Take a deep breath and relax.High school is something that any student can overcome.Make sure you participate in some out-of-class activities because you'll find it easier to make friends.Try to do your best,even if it isn't straight A's. Most important of all,be who you are,whether you're a “fool”,an athlete,or a lower grader.Don't try to pretend to be someone you're not.Now you know the true secrets of high school. 1.The main reason for the author's fear on his first day is that ________.

高中英语模块综合测评1北师大版必修3

模块综合测评(一) Ⅰ.阅读理解(共15小题,每小题2分,共30分) 阅读下列短文,从每题所给的四个选项(A、B、C、D)中,选出最佳选项。 A (2016·山西孝义高一上期末)Alexis was hot and tired.With rage in her voice she shouted,“Pull me up!I give up,I hate this.This is stupid!” It was at that moment when Jason,the adviser on the trip,looked at me and said,“Ed,I'm going to go down and talk with her.” I then shouted down to Alexis,“Hold on!You can do this.We know you can!” Jason grasped another rope,put his climbing harness(系带)on and began to repel down the cliff.Within moments Jason was beside Alexis.She had her cheek directly against the face of the rock with her feet barely resting on a small piece of the cliff that jetted outward.Jason said to Alexis,“I know that you have been on this cliff now for what seems like a long time.Your feet and fingers are cramping(痉挛)up and your forearms feel as though they are on fire.But,Alexis,you are strong,look how far up you are already.You have taken one of the more difficult paths up the cliff.Look Alexis,look at the path you have taken.” At that moment,Alexis moved her cheek away from the rock face and looked down.The bright white chalk she used on her hands to give her a better hold,showed the path where her tired hands had moved her upward on the cliff.Jason was right.Alexis had taken the hardest way up the cliff.Jason then looked straight into Alexis' eyes and in a calm voice he said,“You are not alone out here,there are people who care about you,who want to help you and see you succeed.We are going to do this together.Are you ready?” Slowly she shook her head yes and took a deep breath. 【语篇解读】文章讲述了爱丽克斯在一次攀岩的过程中,爬到一半时自己想放弃了,在詹森的帮助鼓励下最终鼓足了勇气继续攀登。 1.Jason went down the cliff because . A.Alexis took a wrong path B.Alexis was trapped in rocks C.Alexis didn't believe in herself D.Alexis' forearms were badly hurt 【解析】细节理解题。从文章第一段“Hold on!You can do this.We know you

2016-2017学年高中数学模块综合测评1

模块综合测评(一) (时间120分钟,满分150分) 一、选择题(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的) 1.(2016·山西大学附中月考)某公共汽车上有10位乘客,沿途5个车站,乘客下车的可能方式有( ) A.510种 B.105种 C.50种D.3 024种 【解析】 每位乘客都有5种不同的下车方式,根据分步乘法计数原理,共有510种可能的下车方式,故选A. 【答案】 A 2.(1-x)6展开式中x的奇次项系数和为( ) A.32 B.-32 C.0 D.-64 16263646566【解析】 (1-x)6=1-C x+C x2-C x3+C x4-C x5+C x6, 所以x的奇次项系数和为-C-C-C=-32,故选B. 163656 【答案】 B 3.根据一位母亲记录儿子3~9岁的身高数据,建立儿子身高(单位:cm) y^ 对年龄(单位:岁)的线性回归方程=7.19x+73.93,用此方程预测儿子10岁的身高,有关叙述正确的是( ) A.身高一定为145.83 cm B.身高大于145.83 cm C.身高小于145.83 cm D.身高在145.83 cm左右 y^y^ 【解析】 将x=10代入=7.19x+73.93,得=145.83,但这种预测不一定准确.实际身高应该在145.83 cm 左右.故选D. 【答案】 D

4.随机变量X 的分布列如下表,则E (5X +4)等于( ) X 024P 0.3 0.2 0.5 A.16 B .11 C .2.2 D .2.3 【解析】 由表格可求E (X )=0×0.3+2×0.2+4×0.5=2.4,故E (5X +4)=5E (X )+4=5×2.4+4=16.故选A. 【答案】 A 5.正态分布密度函数为f (x )=e -,x ∈R ,则其标准差为( ) 1 2 2π(x -1)28 A .1 B .2 C .4 D .8 【解析】 根据f (x )=e -,对比f (x )=e -知σ=2. 1 σ 2π(x -μ)2 2σ21 2 2π(x -1)28 【答案】 B 6.独立性检验中,假设H 0:变量X 与变量Y 没有关系,则在H 0成立的情况下,P (K 2≥6.635)=0.010表示的意义是( ) A .变量X 与变量Y 有关系的概率为1% B .变量X 与变量Y 没有关系的概率为99.9% C .变量X 与变量Y 没有关系的概率为99% D .变量X 与变量Y 有关系的概率为99% 【解析】 由题意知变量X 与Y 没有关系的概率为0.01,即认为变量X 与Y 有关系的概率为99%. 【答案】 D 7.三名教师教六个班的数学,则每人教两个班,分配方案共有( )A .18种 B .24种 C .45种 D .90种 【解析】 不妨设三名教师为甲、乙、丙.先从6个班中任取两个班分配甲,再从剩余4个班中,任取2个班分配给乙,最后两个班分给丙.由乘法计数原理得分配方案共C ·C ·C =90(种).2 6242【答案】 D

模块1认识计算机综合检测(附答案)

《计算机文化基础》检测试题 模块1 认识计算机 一、单项选择题(每题1分,47小题,共47分。每题所给的四个选项中,只有一个正确答案,请将你的答案填在答题卡上) 1、世界上第一台电子计算机诞生于( B )。 A.1943 B.1946 C.1956 D.1960 2、计算机软件系统由( C )组成。 A.数据库软件和工具软件 B.编辑软件和应用软件 C.系统软件和应用软件 D.程序、相应数据和文档 3、Windows7是计算机系统中的( B )。 A.主要硬件 B.系统软件 C.工具软件 D.应用软件 4、计算机硬件的五大主要部件包括:运算器、控制器、( B )、输出设备和输入设备。 A.键盘 B.存储器 C. CPU D.显示器 5、下列叙述中,正确的是( C )。 A.计算机病毒只在可执行文件中传染 B.只要删除所有感染了病毒的文件就可以彻底消除病毒 C.计算机病毒主要通过读/写移动存储器或Internet网络进行传播 D.计算机杀病毒软件可以查出和清除任意已知的和未知的计算机病毒 6、度量处理器CPU时钟频率的单位是( B )。 A.MIPS B.Hz C.MB D.Mbps 7、计算机的主要技术性能指标( C )。 A.硬盘的容量和内存的容量 B.显示器的分辨率、打印机的性能等配置 C.计算机所配备的语言、操作系统、外部设备 D.字长、运算速度、内/外存容量和CPU的时钟频率 8、将二进制数“11010101001”转换为十进制数为( D )。 A.1001 B.1025 C.1757 D.1705 9、组成计算机指令的两部分是( B )。 A.数据和字符 B.操作码和地址码 C.运算符和运算数 D.运算符和运算结果 10、ANIAC所采用的电子元件是( A )。 A.电子管 B.晶体管 C.中小规模集成电路D.大规模集成电路 11、利用计算机系统时行生产设备的管理、控制和操作的过程一般被称为 ( D )。

2-3模块综合测评(一)解析版

模块综合测评(一) 选修2-3(A 版)(A 卷) (时间:90分钟 满分:120分) 第Ⅰ卷(选择题,共50分) 一、选择题:本大题共10小题,共50分. 1.在? ?? ??x -12x 10的展开式中,x 4的系数为( ) A .-120 B .120 C .-15 D .15 解析:在? ?? ??x -12x 10的展开式中,x 4项是 C 310x 7? ?? ??-12x 3=-15x 4. 答案:C 2.从黄瓜、白菜、油菜、扁豆4种蔬菜中选出3种,分别种在不同土质的三块土地上,其中黄瓜必须种植,则不同的种植方法共有( ) A .24种 B .18种 C .12种 D .6种 解析:先选择一块土地种植黄瓜,有C 13种选择,再从剩余的3种蔬菜 选出2种分别种在剩余的两块土地上有A 23种法,所以有C 13·A 23=18种不同 的种植方法. 答案:B 3.若随机变量ξ服从正态分布N (0,1),已知P (ξ<-1.96)=0.025,则P (|ξ|<1.96)=( ) A .0.025 B .0.050 C .0.950 D .0.975 解析:由随机变量ξ服从正态分布N (0,1), 得P (ξ<1.96)=1-P (ξ≤-1.96). 所以P (|ξ|<1.96)=P (-1.96<ξ<1.96) =P (ξ<1.96)-P (ξ≤-1.96)

=1-2P (ξ≤-1.96) =1-2×0.025=0.950. 答案:C 4.若? ?? ??x 2-1x n 展开式中的所有二项式系数之和为512,则该展开式中的常数项为( ) A .-84 B .84 C .-36 D .36 解析:二项展开式的二项式系数和为2n =512,所以n =9,通项公式为T k +1=C k 9(x 2)9-k ·(-x -1)k =C k 9x 18-2k (-1)k ·x -k =C k 9 x 18-3k ·(-1)k ,令18-3k =0,得k =6,所以常数项为T 7=C 69(-1)6=84. 答案:B 5.在一次独立性检验中,得出列联表如下: A A 合计 B 200 800 1 000 B 180 a 180+a 合计 380 800+a 1 180+a ( ) A .200 B .720 C .100 D .180 解析:A 和B 没有任何关系,也就是说,对应的比例a a +b 和c c +d 基本相等,根据列联表可得2001 000和80180+a 基本相等,检验可知,B 选项满足条件. 答案:B 6. 从某地区的儿童中挑选体操学员,已知儿童体型合格的概率为15,

2018版高中语文苏教版必修3:模块综合测评

模块综合测评 (时间:150分钟分值:150分) 第Ⅰ卷(阅读题,共70分) 一、现代文阅读(35分) (一)论述类文本阅读(9分,每小题3分) 阅读下面的文字,完成1~3题。【导学号:76722113】 无论是天文学家还是普通人,当我们眺望浩瀚星空的时候,每个人心里都不免有这样一种感觉:宇宙太宏大了,相比之下人类和地球都太渺小了。在这茫茫太空之中,有没有其他生命的存在? 虽然人们曾一度想象火星上可能存在生命,但迄今为止,无论在火星还是在太阳系除了地球以外的其他天体上,人们都还没有找到过生命。 以我们现在对生命的理解,液态水在孕育生命中扮演着极为重要的角色。能够存在生命的行星,既不能离中心恒星太近,因为那样会太热而导致水沸腾汽化;也不能离中心恒星太远,那样会太冷而导致水结冰。当然,由于大气气压的不同,其他行星上水的沸点和冰点可能与地球上有所不同,但也不会差得太远。而行星的温度在很大程度上取决于到中心恒星的距离。因此,恒星周围那些适宜生命存在的距离范围,被称为宜居带,处在这些区域内且质量接近地球的行星,才是最有可能存在生命的行星。 近年来,人们使用凌星法找到了很多行星,其中不少是在宜居带内。所谓凌星,是指行星从恒星前经过而挡住一部分恒星的光,这样我们观测到的恒星的亮度会略微减弱。如果我们长期以高精度的设备来监测恒星的亮度,就会发现这样的凌星事件。通过周期性的凌星事件,我们可以确认系外行星的存在。当然,凌星发生的条件是,地球与恒星的连线恰好在这些行星的轨道面上,显然大部分系外行星的轨道面并不满足这一条件。不过,我们总还是有可能幸运地观测到一小部分系外行星。 开普勒卫星是美国于2009年发射的一颗天文卫星,专门“盯着”天鹅座的一小块天空中的恒星,通过凌星法寻找行星。现在,经过几年观测,已经找到了一些宜居带内的类地行星。目前,这些行星大部分还是所谓的“超地球”(指质

创优课堂秋数学人教B必修1练习:模块综合检测 含解析

C .1 D .-1或1 答案:B 解析:(法一)f (-x )=lg(1 1+x +a )=-f (x ), ∴f (-x )+f (x )=0,即lg[(21+x +a )(2 1-x +a )]=0, ∴a =-1. (法二)由f (0)=0得a =-1. 9.某种生物的繁殖数量y (只)与时间x (年)之间的关系式为y =a log 2(x +1),设这种生物第一年有100只,则第7年它们发展到( ) A .300只 B .400只 C .500只 D .600只 答案:A 解析:由题意得100=a log 2(1+1),∴a =100,∴第7年时,y =100log 2(7+1)=300. 10.在同一坐标系中,函数y =x a (a ≠0)和y =ax +1 a 的图象应是如图所示的( ) 答案:B 解析:y =x a 为幂函数,y =ax +1a 为一次函数.对于A ,y =x a 中,a <0,y =ax +1 a 中, 由倾斜方向判断a >0,∴A 不对;对于B ,y =x a 中,a <0,y =ax +1 a 中,a <0,∴B 对;对 于C ,y =x a 中,a >0,y =ax +1 a 中,由图象与y 轴交点知a <0,∴C 不对;对于D ,y =x a 中,a >0,y =ax +1 a 中,由倾斜方向判断a <0,∴D 不对. 11.已知f (x )是R 上的偶函数,且满足f (x +4)=f (x ),当x ∈(0,2)时,f (x )=x +1,则f (3)等于( ) A .2 B .-2 C .1 D .-1 答案:A 解析:由条件知f (3)=f (-1+4)=f (-1).又因为f (-1)=f (1),当x ∈(0,2)时,f (x )=x +1,所以f (1)=2.所以f (3)=f (-1)=f (1)=2. 12.函数f (x )=????? a x (x <1),(a -3)x +4a (x ≥1) 满足对任意x 1≠x 2,都有f (x 1)-f (x 2) x 1-x 2<0成立,则 a 的取值范围是( ) A .(0,34) B .(0,3 4 ] C .(0,1) D .[3,+∞) 答案:B

模块综合测评

模块综合测评 (满分:150分,时间:120分钟) 一、选择题(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的) 1.若集合A={x|-2<x<1},B={x|x<-1或x>3},则A∩B=() A.{x|-2<x<-1} B.{x|-2<x<3} C.{x|-1<x<1} D.{x|1<x<3} A[在数轴上表示出集合A,B,如图所示. 由图知A∩B={x|-2<x<-1}.] 2.已知命题p:x为自然数,命题q:x为整数,则p是q的() A.充分不必要条件B.必要不充分条件 C.充分必要条件D.既不充分也不必要条件 A[若x为自然数,则它必为整数,即p?q. 但x为整数不一定是自然数,如x=-2,即q p.故p是q的充分不必要条件.] 3.若cos α=- 10 10,sin 2α>0,则tan(π-α)等于() A.-3B.3 C.-3 4 D. 3 4 A[∵sin 2α=2sin αcos α>0,cos α=- 10 10, ∴sin α=-310 10,∴tan α= sin α cos α=3, ∴tan(π-α)=-tan α=-3,故选A.] 4.设集合A={1,2},则满足A∪B={1,2,3}的集合B的个数是() A.1B.3 C.4D.8 C[根据题意,满足条件的集合B可以为{3},{1,3},{2,3},{1,2,3}中的任意一个.] 5.若a<b<0,则下列不等式不能成立的是()

A. 1a -b >1a B.1a >1b C .|a |>|b | D .a 2>b 2 A [取a =-2,b =-1,则1a -b >1 a 不成立.] 6.若集合A ={x |ax 2-ax +1<0}=?,则实数a 的取值范围是( ) A .(0,4) B .[0,4) C .(0,4] D .[0,4] D [当a =0时,满足条件;当a ≠0时,由题意知a >0且Δ=a 2-4a ≤0,得0<a ≤4,所以0≤a ≤4.] 7.已知x >0,y >0,且x +2y =2,则xy ( ) A .有最大值为1 B .有最小值为1 C .有最大值为1 2 D .有最小值为1 2 C [因为x >0,y >0,x +2y =2, 所以x +2y ≥2x ·2y ,即2≥22xy ,xy ≤1 2, 当且仅当x =2y ,即x =1,y =1 2时,等号成立. 所以xy 有最大值,且最大值为1 2.] 8.函数f (x )=x 12 -? ?? ?? 12x 的零点个数是( ) A .0 B .1 C .2 D .3 B [函数f (x )=x 12 -? ????12x 的零点个数是方程x 12-? ? ? ??12x =0的解的 个数,即方程x 12 =? ????12x 的解的个数,也就是函数y =x 12与y =? ? ? ? ?12x 的图象的交点个数,在同一坐标系中作出两个函数的图象如图所示,可得交点个数为1.] 9.若函数y =a +sin bx (b >0且b ≠1)的图象如图所示,则函数y =log b (x -a )的图象可能是( )

2016-2017学年高中化学人教版必修一模块综合测评(附答案解析)

模块综合测评 (时间45分钟,满分100分) 一、选择题(本题包括12小题,每小题4分,共48分) 1.(2015·全国卷Ⅰ)我国清代《本草纲目拾遗》中记叙无机药物335种,其中“强水”条目下写道:“性最烈,能蚀五金……其水甚强,五金八石皆能穿滴,惟玻璃可盛。”这里的“强水”是指() A.氨水 B. 硝酸 C.醋D.卤水 【解析】A.氨水有一定的腐蚀作用,对铜的腐蚀比较强,对钢铁腐蚀比较差,对水泥腐蚀不大,氨水可以贮存于塑料、陶瓷等容器中,故A不正确。B.硝酸化学性质活泼,能与多种物质反应,它是一种强氧化剂,它可腐蚀各种金属(铂和金除外)和材料,故B正确。C.醋具有弱酸性,具有酸的通性,没有强氧化性,不能腐蚀“五金八石”,醋酸也可贮存于塑料瓶,故C不正确。D.卤水又称作卤碱,其主要成分为氯化镁、氯化钠和一些金属离子,是制作食盐过程中渗滤出来的液体,在日常生活中常用于制作豆腐,大量吞服卤水可引起消化道腐蚀,镁离子被人体吸收后对心血管及神经系统均有抑制作用,故D不正确。 【答案】 B 2.下列有关说法中,不正确的是() A.焰火的五彩缤纷是某些金属元素的性质的展现 B.SiO2可用于制造光导纤维,其性质稳定,不溶于强酸、强碱 C.“光化学烟雾”“硝酸型酸雨”的形成都与氮氧化物有关 D.根据分散质微粒直径大小可以将分散系分为溶液、胶体和浊液 【解析】B项,SiO2可用于制造光导纤维,其性质稳定,一般情况下不能与强酸反应,但能与强碱发生反应,如2NaOH+SiO2===Na2SiO3+H2O,错误。 【答案】 B 3.(2015·广东高考)水溶液中能大量共存的一组离子是() A.NH+4、Ba2+、Br-、CO2-3 B.Cl-、SO2-3、Fe2+、H+ C.K+、Na+、SO2-4、MnO-4 D.Na+、H+、NO-3、HCO-3

选修2-1 模块综合检测(B)

选修2-1 模块综合检测(B) 一、选择题 1、如图,在长方体ABCD—A1B1C1D1中,AB=BC=2,AA1=1,则BC1与平面BB1D1D所成角的正弦值为( ) A. 6 3 B. 25 5 C. 15 5 D. 10 5 2、“a>0”是“|a|>0”的( ) A.充分不必要条件 B.必要不充分条件 C.充要条件 D.既不充分也不必要条件 实用文档

实用文档 3、若双曲线x 2a 2- y 2 b 2 =1 (a >0,b >0)的右支上到原点和右焦点距离相等的点有两个,则双曲线离 心率的取值范围是( ) A .e > 2 B .12 D .1

实用文档 A.x 22-y 24=1 B.x 24-y 2 2 =1 C.y 24-x 22=1 D.y 22-x 2 4 =1 7、已知a =(cos α,1,sin α),b =(sin α,1,cos α),则向量a +b 与a -b 的夹角是( ) A .90° B.60° C.30° D.0° 8、设双曲线x 2a 2- y 2b 2 =1(a >0,b >0)的渐近线与抛物线y =x 2+1相切,则该双曲线的离心率等于 ( ) A. 3 B .2 C. 5 D.6 9、已知正四棱柱ABCD —A 1B 1C 1D 1中,AA 1=2AB ,E 为AA 1的中点,则异面直线BE 与CD 1 所成角的余弦值为( ) A.10 10 B.15 C. 310 10 D.3 5

模块综合检测(一)

模块综合检测(一) (时间120分钟,满分150分) 一、选择题(本题共10小题,每小题6分,共60分) 1.命题“?x 0∈R,2x 0-3>1”的否定是( ) A .?x 0∈R,2x 0-3≤1 B .?x ∈R,2x -3>1 C .?x ∈R,2x -3≤1 D .?x 0∈R,2x 0-3>1 解析:选C 由特称命题的否定的定义即知. 2.已知条件甲:ab >0;条件乙:a >0,且b >0,则( ) A .甲是乙的充分但不必要条件 B .甲是乙的必要但不充分条件 C .甲是乙的充要条件 D .甲是乙的既不充分又不必要条件 解析:选B 甲?/乙,而乙?甲. 3.对?k ∈R ,则方程x 2+ky 2=1所表示的曲线不可能的是( ) A .两条直线 B .圆 C .椭圆或双曲线 D .抛物线 解析:选D 分k =0,1及k >0且k ≠1,或k <0可知:方程x 2+ky 2=1不可能为抛物线. 4.下列说法中正确的是( ) A .一个命题的逆命题为真,则它的逆否命题一定为真 B .“a >b ”与“a +c >b +c ”不等价 C .“a 2+b 2=0,则a ,b 全为0”的逆否命题是“若a ,b 全不为0,则a 2+b 2≠0” D .一个命题的否命题为真,则它的逆命题一定为真 解析:选D 否命题和逆命题互为逆否命题,有着一致的真假性,故选D. 5.已知空间向量a =(1,n,2),b =(-2,1,2),若2a -b 与b 垂直,则|a |等于( ) A.5 32 B.212 C.372 D.3 52

解析:选D 由已知可得2a -b =(2,2n,4)-(-2,1,2)=(4,2n -1,2). 又∵(2a -b )⊥b ,∴-8+2n -1+4=0. ∴2n =5,n =52.∴|a |= 1+4+254=3 52 . 6.下列结论中,正确的为( ) ①“p 且q ”为真是“p 或q ”为真的充分不必要条件;②“p 且q ”为假是“p 或q ”为真的充分不必要条件;③“p 或q ”为真是“綈p ”为假的必要不充分条件;④“綈p ”为真是“p 且q ”为假的必要不充分条件. A .①② B .①③ C .②④ D .③④ 解析:选B p ∧q 为真?p 真q 真?p ∨q 为真,故①正确, 由綈p 为假?p 为真?p ∨q 为真,故③正确. 7.已知双曲线的中心在原点,离心率为3,若它的一个焦点与抛物线y 2=36x 的焦点重合,则该双曲线的方程是( ) A.x 281-y 2 54 =1 B.y 281-x 254=1 C.x 227-y 2 54=1 D.y 227-x 254 =1 解析:选C 由已知得c a =3,c =9,∴a 2=27,b 2=54,且焦点在x 轴,所以方程为x 227 -y 254 =1. 8.若直线y =2x 与双曲线x 2a 2-y 2 b 2=1(a >0,b >0)有公共点,则双曲线的离心率的取值范围为( ) A .(1,5) B .(5,+∞) C .(1,5] D .[5,+∞) 解析:选B 双曲线的两条渐近线中斜率为正的渐近线为y =b a x .由条件知,应有b a >2, 故e =c a =a 2+b 2 a = 1+???? b a 2> 5. 9.已知F 1(-3,0),F 2(3,0)是椭圆x 2m +y 2 n =1的两个焦点,点P 在椭圆上,∠F 1PF 2=α.当α=2π3 时,△F 1PF 2面积最大,则m +n 的值是( ) A .41 B .15 C .9 D .1

相关文档
相关文档 最新文档